我在aspx页面上添加了一个按钮,我想要点击该按钮进行新的Web用户控制。例如。如果一个人有多个地址,他可以点击该按钮,并可以添加address1,address2,address3
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
</head>
<body>
<form id="form1" runat="server">
<div>
<table>
<tr>
<td>
<asp:Label ID="Lbl_name" runat="server" Text="Name"></asp:Label>
</td>
<td>
<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox>
</td>
</tr>
<tr>
<td>
<asp:Label ID="Lbl_age" runat="server" Text="Age"></asp:Label>
</td>
<td>
<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox>
</td>
</tr>
</table>
<!-- Add the web user control in asp -->
<WebUserControl:WebTag id="MyControl" runat="server"/>
<asp:Button ID="Btn_add" runat="server" Text="Add" />
<br />
<td>
<asp:Button ID="Button1" runat="server" Text="Submit" OnClick="Button1_Click" />
</td>
<br /><br />
</div>
</form>
</body>
</html>
答案 0 :(得分:0)
您可以使用JQuery完成您的功能,就像在这个jsFiddle
中一样<强> HTML 强>
<div id="myDiv">
<div id="item1">
<input id="txt1" name="txt1" type="text"></input><input id="cmdAdd1" type="button" value="Add"></input>
</div> </div>
<强>的Javascript 强>
var itemCount = 1;
$('#cmdAdd1').click(function(){addNewItem();});
function addNewItem(){
var thisItem = itemCount;
// Make last text box readonly
$('#txt' + itemCount).attr('readonly', 'readonly');
// Change button to Remove button
$('#cmdAdd' + itemCount).attr('value', 'Remove');
$('#cmdAdd' + itemCount).unbind();
$('#cmdAdd' + itemCount).click(function(){removeItem(thisItem );});
// Add new line with text field and button
itemCount++;
var newItem = '<div id="item' + itemCount + '">'
newItem += '<input id="txt' + itemCount + '" name="txt' + itemCount + '" type="text"></input>';
newItem += '<input id="cmdAdd' + itemCount + '" type="button" value="Add"></input>';
newItem += "</div>";
$('#myDiv').append(newItem);
$('#cmdAdd' + itemCount).click(function(){addNewItem();});
}
function removeItem(i){
$('#item' + i).remove();
}
将表单发回服务器后,您可以通过遍历表单控件来遍历字段。
<强> C#强>
int n=1;
while (Request["txt" + n] != null)
{
Console.WriteLine(Request["txt" + n]);
n++;
}