+------------+--------+-----------+---------------+
| paydate | salary | ninumber | payrollnumber |
+------------+--------+-----------+---------------+
| 2015-05-15 | 1000 | jh330954b | 6 |
| 2015-04-15 | 1250 | jh330954b | 5 |
| 2015-03-15 | 800 | jh330954b | 4 |
| 2015-02-15 | 894 | jh330954b | 3 |
| 2015-05-15 | 500 | ew56780e | 6 |
| 2015-04-15 | 1500 | ew56780e | 5 |
| 2015-03-15 | 2500 | ew56780e | 4 |
| 2015-02-15 | 3000 | ew56780e | 3 |
| 2015-05-15 | 400 | rt321298z | 6 |
| 2015-04-15 | 582 | rt321298z | 5 |
| 2015-03-15 | 123 | rt321298z | 4 |
| 2015-02-15 | 659 | rt321298z | 3 |
+------------+--------+-----------+---------------+
以上列表是我数据库中的数据。我需要得到每个人之前3个工资的平均值并输出。
我不知道从哪里开始,所以到目前为止我无法提供任何工作。
答案 0 :(得分:5)
在SQL Server中,您可以使用row_number()
获取子查询中的最后三个工资。然后使用avg()
:
select ninumber, avg(salary)
from (select t.*,
row_number() over (partition by ninumber order by payrollnumber desc) as seqnum
from table t
) t
where seqnum <= 3
group by ninumber;