Question

条件不起作用因为使用TO_CHAR（），但如何提取时间？以下是我的询问：

select sum (FREIGHT * STAX_RATE / 100)
from (select INVM.FREIGHT as FREIGHT , MAX(INVT.STAX_RATE) as STAX_RATE
      from invm inner join INVT on INVM.I_B_NO = INVT.I_B_NO
      where invm.i_b_dt between '04/01/2015 00:00:00' and '04/01/2015 00:00:00'
      group by INVM.FREIGHT)

Answer 1

看起来您只对时间感兴趣，但对日期部分不感兴趣。假设FROM_TIME和TO_TIME的数据类型为DATE或TIMESTAMP，您可以这样做：

select *
FROM SUPPLY_TIMING
WHERE EXTRACT(HOUR FROM SYSDATE) + EXTRACT(MINUTE FROM SYSDATE)/60 
   BETWEEN EXTRACT(HOUR FROM FROM_TIME) + EXTRACT(MINUTE FROM FROM_TIME)/60
       AND EXTRACT(HOUR FROM TO_TIME) + EXTRACT(MINUTE FROM TO_TIME)/60

Answer 2

乍一看，我的猜测是你的格式掩码是造成问题的原因。 HH组件会以12小时格式为您提供时间，因此下午1点将返回01，我认为如果您使用HH24，则会获得13，使字符串比较按预期工作：

SELECT *
FROM SUPPLY_TIMING
WHERE TO_CHAR (SYSDATE, 'HH24:Mi') >= TO_CHAR (FROM_TIME, 'HH24:Mi')
AND TO_CHAR (SYSDATE, 'HH24:Mi') <= TO_CHAR (TO_TIME, 'HH24:Mi')

当前时间的条件大于或等于时间和当前时间小于或等于ORACLE中的时间

2 个答案: