Question

所以这是我的代码段：

double numericalMethod::splineLinearInterpolation(){

int n, i=0;
double x[100], y[100], s[100],a;
cout << "Enter no. of sample points : \n";
cout << "\n";
cin  >> n;
cout << "\n";
cout << "Enter all values of x and corresponding functional value y :  \n";
cout << "\n";
cout << "x | y \n";
for (i=0; i<n; i++){
    cin >> x[i] >> y[i];
}
cout << "\n";
cout << "Enter the value of  x for which you would like to calculate the estimated value of y : \n ";
cout << "\n";
cin  >> a;
while (a<x[0] or a>x[n]){
    cout << "The selected value of x must belong to the domain [" << x[0] << "," << x[4] << "] \n" ;
    cout << "\n";
    cout << "Reenter the value of x please : ";
    cout << "\n";
    cin  >> a;
}
cout << "\n";

for (i=0; i<n-1; i++){
   s[i]=y[i] + ((y[i+1]-y[i])/(x[i+1]-x[i]))*(a-x[i]);
   if (a>=x[i] and a<=x[i+1])
       cout << "s[" << i << "] =" << s[i] << "   when " << x[i] << " <= x <=" << x[i+1] <<endl;

}
return 0;

}

x是一个数组

当我的程序进入循环时它永远不会退出

虽然当我用常数切换x [0]和x [n]时它完全运行

任何想法？并谢谢

Answer 1

你正在以这种方式阅读：

for (i = 0; i < n; i++) {
  cin >> x[i] >> y[i];
}

数组x的位置值为[0，N-1]

但在此期间：

while (a < x[0] or a > x[n] ){

你试图访问数组的位置N，如果没有初始化，它将是一个随机数。

while循环继续运行

1 个答案: