如何从表EMP中检索每个部门的员工列表到逗号分隔的新表中 类似的东西:
[column x:ie deptno] [column y:ie ename]
--------------------------
7 Jesus, María, José
5 Staz, Przemek, Tomek
6 John, Jane, Bob
下面的表是我想从函数concatenate_list编译
中得到我的结果的地方CREATE TABLE Z
(
x NUMBER(2) NOT NULL,
y VARCHAR2 (4000) NOT NULL
);
SET SERVEROUTPUT ON
CREATE OR REPLACE FUNCTION concatenate_list (xy_cursor IN SYS_REFCURSOR)
RETURN VARCHAR2
IS
lret VARCHAR2(30000);
ltemp VARCHAR2(30000);
BEGIN
LOOP
FETCH xy_cursor
INTO ltemp;
EXIT WHEN xy_cursor%notfound;
lret := lret || ',' || ltemp;
END LOOP;
RETURN LTRIM(lret, ',');
END;
/
SHOW ERRORS
如何从“Function concatenate_lit compile”中插入结果并获得如上所述的结果。 也许使用这样的东西:
INSERT INTO Z( x, y) SELECT e1.x,
concatenate_list(CURSOR(SELECT e2.y FROM EMP e2 WHERE e2.x= e1.x));
但是如何在PL / SQL块中设置它
答案 0 :(得分:1)
这可能会对你有帮助。
declare
type cur_name is ref cursor;
emp_name cur_name;
v_ename emp.ename%type;
v_all_ename varchar2(1000);
v_deptno emp.deptno%type;
cursor c is select deptno,cursor(select ename from emp e where e.deptno=f.deptno) from emp f group by deptno;
begin
open c;
loop
fetch c into v_deptno,emp_name;
exit when c%notfound;
loop
fetch emp_name into v_ename;
exit when emp_name%notfound;
v_all_ename:=v_all_ename||v_ename;
v_all_ename:=v_all_ename||',';
end loop;
dbms_output.put_line(v_deptno||' '||v_all_ename);
v_all_ename:='';
end loop;
close c;
end;