Question

我面临着apache服务器的问题，我们编写了代码，如果在表单字段中输入的url有效，它将显示错误消息，当我通过django developement服务器运行代码时，它工作正常，显示错误消息，但在通过apache运行时，则不会显示错误消息，只返回该页面本身。这是python和html下面的代码：

objc= {
    "addRecipeBttn": "/project/add",
    "addRecipeUrlBttn": "/project/add/import",
    }

def __showAddRecipe__(request):
    global objc
    #global objc
    if "userid" in request.session:
        objc["ErrorMsgURL"]= ""
        try:
            urlList= request.POST
            URL= str(urlList['url'])
            URL= URL.strip('http://')
            URL= "http://" + URL

            recipe= __addRecipeUrl__(URL)

            if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'):
                #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL"
                objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL"
                print "here global_context =", objc
                return HttpResponseRedirect("/project/add/import/")
                #return render_to_response('addRecipeUrl.html', objc, context_instance = RequestContext(request))
            else:
                objc["recipe"] = recipe
                return render_to_response('addRecipe.html',
                    objc,
                    context_instance = RequestContext(request))
        except:
            objc["recipe"] = ""
            return render_to_response('addRecipe.html',
                objc,
                context_instance = RequestContext(request))
    else:
        login_redirect['next']= "/project/add/"
        return HttpResponseRedirect("/project/login")



def __showAddRecipeUrl__(request):
    global objc
    if "userid" in request.session:
        return render_to_response('addRecipeUrl.html',
            objc, 
            context_instance = RequestContext(request))
    else:
        login_redirect['next']= "/project/add/import/"
        return HttpResponseRedirect("/project/login")
_

HTML文件： -

请检查并告诉我是否有人可以在这个问题上提供帮助，它在django开发服务器上工作。

谢谢 Suhail

Answer 1

嘿伙计们，感谢你的支持，问题解决了，我这样做了。

def showAddRecipe(request):
    #global objc
    if "userid" in request.session:
        objc["ErrorMsgURL"]= ""
        try:
            urlList= request.POST
            URL= str(urlList['url'])
            URL= URL.strip('http://')
            URL= "http://" + URL

            recipe= __addRecipeUrl__(URL)

            if (recipe == 'FailToOpenURL') or (recipe == 'Invalid-website-URL'):
                #request.session["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL"
                objc["ErrorMsgURL"]= "Kindly check URL, Please enter a valid URL"
                print "here global_context =", objc
                arurl= HttpResponseRedirect("/project/add/import/")
                arurl['ErrorMsgURL']= objc["ErrorMsgURL"]
                return (arurl)
            else:
                objc["recipe"] = recipe
                return render_to_response('addRecipe.html',
                    objc,
                    context_instance = RequestContext(request))
        except:
            objc["recipe"] = ""
            return render_to_response('addRecipe.html',
                objc,
                context_instance = RequestContext(request))
    else:
        login_redirect['next']= "/project/add/"
        return HttpResponseRedirect("/project/login")

在django开发服务器上工作但不在apache上工作

1 个答案: