我的流程如下所示,我希望将消息重新传递2次,然后重新传递
重新传递已经用完SAD
要打印的记录器。但是在组件抛出异常后,重新传递机制不会启动
<vm:connector name="VM" validateConnections="true" doc:name="VM" />
<flow name="TriggerFlow" >
<http:listener config-ref="Orders_HTTP_Listener_Configuration" path="/rollback" allowedMethods="GET" doc:name="1080/rollback" />
<vm:outbound-endpoint exchange-pattern="request-response" path="txFlow" doc:name="VM" connector-ref="VM" responseTimeout="60000">
</vm:outbound-endpoint>
</flow>
<flow name="TxFlow" >
<vm:inbound-endpoint exchange-pattern="request-response" path="txFlow" doc:name="case1" connector-ref="VM" responseTimeout="60000">
<xa-transaction action="ALWAYS_BEGIN"/>
</vm:inbound-endpoint>
<scripting:component doc:name="Groovy">
<scripting:script engine="Groovy"><![CDATA[throw new RuntimeException();]]></scripting:script>
</scripting:component>
<rollback-exception-strategy maxRedeliveryAttempts="3" doc:name="Rollback Exception Strategy">
<logger message="Will rollback #[payload]" level="INFO" doc:name="Logger"/>
<on-redelivery-attempts-exceeded>
<logger message="Redelivery is exhaused SAD " level="INFO" doc:name="Logger"/>
</on-redelivery-attempts-exceeded>
</rollback-exception-strategy>
</flow>
答案 0 :(得分:2)
在与MuleSoft交谈后,我终于得到了答案。更新的流程应如下所示,VM应该是单向的,并且TxFlow的处理策略应该是同步的。如果VM是请求响应,那么它的行为更像是一个没有队列的flow-ref,因此没有重新传递......