我为图节点定义了一个节点类型:
struct node{
int data;
int neighboursNumber;
node * neighbours;
};
我正在尝试为每个节点添加一些像这样的邻居:
node * n1 = (node *)malloc(sizeof(node));
n1->data = 1;
n1->neighboursNumber = 2;
n1->neighbours = (node *)malloc(sizeof(node) * n1->neighboursNumber);
node * n2 = (node *)malloc(sizeof(node));
n2->data = 2;
n2->neighboursNumber = 1;
n2->neighbours = (node *)malloc(sizeof(node) * n2->neighboursNumber);
node * n3 = (node *)malloc(sizeof(node));
n3->data = 3;
n3->neighboursNumber = 1;
n3->neighbours = (node *)malloc(sizeof(node) * n3->neighboursNumber);
n1->neighbours[0] = n2;
n1->neighbours[1] = n3;
n2->neighbours[0] = n1;
n3->neighbours[0] = n1;
但是我在构建时遇到错误
error C2679: binary '=' : no operator found which takes a right-hand operand
of type 'node *' (or there is no acceptable conversion)
难道没有正确的方法吗?
答案 0 :(得分:1)
而不是
struct node{
int data;
int neighboursNumber;
node * neighbours;
};
写下这个:
typedef struct _node{
int data;
int neighboursNumber;
struct _node * neighbours;
} node;
但正如其他人在评论中指出的那样,邻居应该
struct _node ** neighbors;
答案 1 :(得分:0)
(借用)我认为这对你有用......
_container
到目前为止......我不确定你是如何使用它的,但我不认为你的邻居在逻辑意义上是对齐的...... ??
typedef struct _node {
int data;
int neighboursNumber;
struct _node **neighbours;
} node;
int main( void ) {
node *n1 = (node *)malloc(sizeof(node));
n1->data = 1;
n1->neighboursNumber = 2;
n1->neighbours = (node **)malloc(sizeof(node *) * n1->neighboursNumber);
node * n2 = (node *)malloc(sizeof(node));
n2->data = 2;
n2->neighboursNumber = 1;
n2->neighbours = (node **)malloc(sizeof(node *) * n2->neighboursNumber);
node * n3 = (node *)malloc(sizeof(node));
n3->data = 3;
n3->neighboursNumber = 1;
n3->neighbours = (node **)malloc(sizeof(node *) * n3->neighboursNumber);