Question

如何使用第二个子选择中第一个子选择的END_DATE / START_DATE？提供的值仅为示例。（06/01/2010）。

SELECT "PROJECT"."ID", 
        "PROJECT"."CLIENT", 
        "PROJECT"."NAME", 
        "PROJECT"."STATE", 
        "PROJECT"."EARLIEST_START", 
        "PROJECT"."LATEST_END", 
        "PROJECT"."EFFORT", 
        "PROJECT"."LINK", 
        "PROJECT"."STATUS", 
        "PROJECT"."DESCRIPTION", 
        (SELECT SUM((END_DATE - START_DATE + 1) * (WORKLOAD / 100)) 
           FROM WORKITEM WHERE PROJECT = PROJECT.ID
        ) AS "P_A", 
        (SELECT COUNT(*) 
          FROM PUBLIC_HOLIDAY 
          WHERE HOLIDAY_DATE BETWEEN TO_DATE('06/1/2010','MM/DD/YYYY') AND 
                                   TO_DATE('06/2/2010','MM/DD/YYYY')) AS P_B,
        "PROJECT_STATE"."STATE", 
        "PERSON"."DISPLAY_NAME" AS "RESPONSIBLE" 
        FROM "PROJECT"
        INNER JOIN "PROJECT_STATE" ON PROJECT.STATE = PROJECT_STATE.ID
        INNER JOIN "PERSON" ON RESPONSIBLE = PERSON.ID
        WHERE (PROJECT.CLIENT = '1') AND (PROJECT.STATE = 1)
        ORDER BY "PROJECT"."NAME" ASC

Answer 1

以下是在多个地方使用start_date和end_date的一种方法

with (select to_date('06/01/2010','MM/DD/YYYY') as start_date,  
             to_date('06/02/2010','MM/DD/YYYY') as end_date  
        from dual) as q1  
select project.id,
       project_state.state, 
       q1.start_date,
       q1.end_date,
       (SELECT SUM((q1.END_DATE - q1.START_DATE + 1) * (WORKLOAD / 100)) 
       FROM WORKITEM WHERE PROJECT = PROJECT.ID) AS P_A 
 from project  
 join project_state on project_state.id = project.state 
 join q1 on 1=1

Answer 2

你做不到。您可以使用连接从两者中创建单个子选择，并将新的复合子选择从SELECT部分移动到主查询的FROM部分。

Answer 3

这就是你要找的东西

    SELECT "PROJECT"."ID", 
        "PROJECT"."CLIENT", 
        "PROJECT"."NAME", 
        "PROJECT"."STATE", 
        "PROJECT"."EARLIEST_START", 
        "PROJECT"."LATEST_END", 
        "PROJECT"."EFFORT", 
        "PROJECT"."LINK", 
        "PROJECT"."STATUS", 
        "PROJECT"."DESCRIPTION", 
        (SELECT SUM((END_DATE - START_DATE + 1) * (WORKLOAD / 100)) 
           FROM WORKITEM WHERE PROJECT = PROJECT.ID
        ) AS "P_A", 
        (SELECT COUNT(*) 
          FROM PUBLIC_HOLIDAY 
          WHERE HOLIDAY_DATE BETWEEN NVL(END_DATE,SYSDATE) AND 
                                   NVL(START_DATE,SYSDATE)) AS P_B,
        "PROJECT_STATE"."STATE", 
        "PERSON"."DISPLAY_NAME" AS "RESPONSIBLE" 
        FROM "PROJECT"
        INNER JOIN "PROJECT_STATE" ON PROJECT.STATE = PROJECT_STATE.ID
        INNER JOIN "PERSON" ON RESPONSIBLE = PERSON.ID
        LEFT JOIN "WORKITEM" ON WORKITEM.PROJECT = WORKITEM.ID 
        WHERE (PROJECT.CLIENT = '1') AND (PROJECT.STATE = 1)
        ORDER BY "PROJECT"."NAME" ASC

ORACLE中的SQL Where子句

3 个答案: