我遇到了选择查询的问题
对于select coid,model,km,year
和AC
的所有车辆,我需要MP3
。
我写了这个SQL:
select distinct
vehicle.vehid, model, km, year
from
vehicle, models, extras, veh_extras
where
models.modid = vehicle.modid
and vehicle.vehid = veh_extras.vehid
and extras.extraid = veh_extras.extraid
and (descr = 'AC' or descr = 'mp3')
但我觉得这是错的。 Extras.desc
是用于描述额外内容的列。
答案 0 :(得分:4)
SELECT v.vehid, m.model, v.km, v.year
FROM vehicle v
JOIN model m ON v.modid = m.modid
WHERE EXISTS ( SELECT 'a'
FROM extras e
JOIN veh_extras ve ON e.id = ve.extraid
WHERE ve.vehid = v.vehid
AND e.descr = 'AC'
)
AND EXISTS ( SELECT 'a'
FROM extras e
JOIN veh_extras ve ON e.id = ve.extraid
WHERE ve.vehid = v.vehid
AND e.descr = 'mp3'
)
这可能不是最好的方法......但是如果你需要搜索更多的额外内容,只需添加另一个EXISTS条件
答案 1 :(得分:3)
假设你想要同时拥有AC和MP3的车辆,那么一个选项就是多次加入veh_extras
表:
select distinct v.vehid, m.model
from vehicle v
join models m on m.modid = v.modid
join veh_extras ve on v.vehid = ve.vehid
join extras e on ve.extraid = e.extraid and e.descr = 'AC'
join veh_extras ve2 on v.vehid = ve2.vehid
join extras e2 on ve2.extraid = e2.extraid and e2.descr = 'MP3'
另一种选择是使用案例聚合:
select v.vehid, m.model
from vehicle v
join models m on m.modid = v.modid
join veh_extras ve on v.vehid = ve.vehid
join extras e on ve.extraid = e.extraid
group by v.vehid, m.model
having sum(case when e.descr = 'AC' then 1 else 0 end) > 0
and sum(case when e.descr = 'MP3' then 1 else 0 end) > 0
BTW - 我省略了一些补救栏目 - 很容易将这些列添加回来......
答案 2 :(得分:1)
但我认为错了。
即使它起作用,也不是推荐的方式。
尽量避免使用逗号分隔的JOINS。而是试着像这样使用JOINS:
select distinct v.vehid,model,km,year
from vehicle v inner join models m on v.modid = m.modid
inner join veh_extras ve on ve.vehid = v.vehid
inner join extras e on e.extraid = ve.extraid
where
e.descr='AC' or e.descr='mp3'