输出量是否有某种限制Python 3.4允许一次使用write()方法?

时间:2015-05-06 14:42:46

标签: python srt

我在我的代码末尾的write()方法行旁边放置了trailing print()方法,以测试输出文件不完整的原因。但是,print()输出是我所期望的“所有东西”;而write()输出被一个令人困惑的数量关闭(200个'东西'中只有150个)。 输出的参考图像IDLE versus external output file

仅供参考:Win 7 64 // Python 3.4.2

我的模块采用SRT字幕文件('test.srt')并返回我创建的列表对象;特别是,有一个220列表条目的形式:[[(index),[time],string]]

times = open('times.txt', 'w')

### A portion of Riobard's SRT Parser: srt.py
import re

def tc2ms(tc):
    ''' convert timecode to millisecond '''

    sign    = 1
    if tc[0] in "+-":
        sign    = -1 if tc[0] == "-" else 1
        tc  = tc[1:]

    TIMECODE_RE     = re.compile('(?:(?:(?:(\d?\d):)?(\d?\d):)?(\d?\d))?(?:[,.](\d?\d?\d))?')
    match   = TIMECODE_RE.match(tc)
    try: 
        assert match is not None
    except AssertionError:
        print(tc)
    hh,mm,ss,ms = map(lambda x: 0 if x==None else int(x), match.groups())
    return ((hh*3600 + mm*60 + ss) * 1000 + ms) * sign

# my code
with open('test.srt') as f:
    file = f.read()

srt = []

for line in file:
    splitter = file.split("\n\n")

# SRT splitter
i = 0
j = len(splitter)
for items in splitter:
    while i <= j - 2:
        split_point_1 = splitter[i].index("\n")
        split_point_2 = splitter[i].index("\n", split_point_1 + 1)
        index = splitter[i][:split_point_1]
        time = [splitter[i][split_point_1:split_point_2]]
        time = time[0][1:]
        string = splitter[i][split_point_2:]
        string = string[1:]
        list = [[(index), [time], string]]
        srt += list
        i += 1

# time info outputter
i = 0
j = 1
for line in srt:
    if i != len(srt) - 1:
        indexer = srt[i][1][0].index(" --> ")
        timein = srt[i][1][0][:indexer]
        timeout = srt[i][1][0][-indexer:]
        line_time = (tc2ms(timeout) - tc2ms(timein))/1000
        space_time = ((tc2ms((srt[j][1][0][:indexer]))) - (tc2ms(srt[i][1][0][-indexer:])))/1000
        out1 = "The space between Line " + str(i) + " and Line " + str(j) + " lasts " + str(space_time) + " seconds." + "\n"
        out2 = "Line " + str(i) + ": " + str(srt[i][2]) + "\n\n"
        times.write(out1)
        times.write(out2)
        print(out1, end="")
        print(out2)
        i += 1
        j += 1
    else:
        indexer = srt[i][1][0].index(" --> ")
        timein = srt[i][1][0][:indexer]
        timeout = srt[i][1][0][-indexer:]
        line_time = (tc2ms(timeout) - tc2ms(timein))/1000
        outend = "Line " + str(i) + ": " + str(srt[i][2]) + "\n<End of File>"
        times.write(outend)
        print(outend)

我的两个write()方法输出文件分别只打印出其中正确打印到屏幕上的220件物品中的~150或~200件物品。

1 个答案:

答案 0 :(得分:1)

完成编写后,您希望关闭您的bytes = (byte[])sdr["Data"]; byte[] buffer = bytes; MemoryStream memory = new MemoryStream(buffer.ToArray()); string decoded = Encoding.UTF8.GetString(memory.ToArray()); XPathDocument myXPathDoc = new XPathDocument(decoded); XslCompiledTransform myXslTrans = new XslCompiledTransform(); myXslTrans.Load(Server.MapPath("~/Xsl/CCD.xsl")); XmlTextWriter myWriter = new XmlTextWriter("some.html", null); myXslTrans.Transform(myXPathDoc, null, myWriter); 文件;操作系统使用写缓冲区来加速文件I / O,一次性收集要写入磁盘的较大数据块;关闭文件会刷新缓冲区:

times

考虑在times.close() 块中打开文件:

with