订购表
o_id customer_id drink_id food_id
---- ----------- -------- -------
1 22 10 12
2 22 11 12
3 22 11 12
4 44 11 13
5 22 11 13
标题表
t_id title_id type title
---- -------- ---- -----
1 10 drink Black Velvet
2 11 drink Mojito
3 12 food Rice
4 13 food Meat
例如 customer_id = 22
o_id drink_id drink_title food_id food_title
---- -------- ----------- ------- ----------
1 10 Black Velvet 12 Rice
2 11 Mojito 12 Rice
3 11 Mojito 12 Rice
5 11 Mojito 13 Meat
我不知道是否有正确的方法:
SELECT
查询?JOIN
? (如果是这种情况,查询应该如何?)答案 0 :(得分:4)
您可以多次name := "Transaction Fraud"
version := "1.0"
scalaVersion := "2.10.4"
libraryDependencies += "org.apache.spark" %% "spark-core" % "1.3.1" % "provided"
resolvers ++= Seq(
"Akka Repository" at "http://repo.akka.io/releases/",
"Spray Repository" at "http://repo.spray.cc/")
join
表到title
表:
orders
答案 1 :(得分:1)
您可以使用某个功能并获得结果:
SELECT o_id,
drink_id,
getOrderTitle(drink_id) AS drink_title,
food_id,
getOrderTitle(food_id) AS food_title
FROM Order;
创建函数:
CREATE OR REPLACE FUNCTION getOrderTitle (startValue IN NUMBER)
RETURN VARCHAR2 IS
orderTitle VARCHAR2 (20);
BEGIN
SELECT title
INTO orderTitle
FROM Title
WHERE title_id = startValue;
RETURN orderTitle;
END;
/