Question

所以我有这个.txt文件，每行有100多行和一个值我如何读取特定行的值并将其用于if？
让我们说我想读取第34行，看看该行的值是0还是1。我真的不知道如何解释但我正在考虑这样的事情。我可以分配＆＃34; print（第34行）和＃34;一个整数，然后将整数与0或1进行比较？请记住，我没有使用python的经验。

f = open("NT.txt",'r')
lines = f.readlines()
if print(lines[34]) == 1:
    print("something")

Answer 1

if lines[34].strip() == "1":

因为文件总是文字......可能会回答你的问题吗？

（请注意，因为列表以0 lines[34]开头是第35行）

有些人可能会告诉你尝试

if int(lines[34])==1:

您听说print而不是int

Answer 2

As @JoranBeasley pointed out to my solution in the comment up there, anything read in from a text file is read in as...text (duh!). It would need to be converted to an int, so the proper if statement should be:

if int(lines[34].strip()) == 1:
    # Do something here.

Additionally, most folks would probably open the text file using a with statement, so that it closes automagically when you're done using it:

with open('NT.txt', 'r') as f:
    lines = f.readlines()
if int(lines[34].strip()) == 1:
    # Do something here.

Answer 3

This should work:

f=open('NT.txt', 'r')
lines=f.readlines()

if int(lines[34])==1:
    print('something')

从文件

3 个答案: