Question

给定一个网址和一个查询字符串，如何获取查询字符串与网址组合产生的网址？

我正在寻找类似于.htaccess的qsa的功能。我意识到完全手工实现这将是相当简单的，但有没有内置函数来处理查询字符串，可以简化或完全解决这个问题？

示例输入/结果集：

Url="http://www.example.com/index.php/page?a=1"
QS ="?b=2"
Result="http://www.example.com/index.php/page?a=1&b=2"

-

Url="page.php"
QS ="?b=2"
Result="page.php?b=2"

Answer 1

如何使用不使用PECL扩展且不是大量复制和粘贴功能的东西？它仍然有点复杂，因为你将两个查询字符串拼接在一起并希望以不仅$old .= $new;

的方式进行拼接

我们将使用parse_url从所需的网址parse_str中提取查询字符串，以解析您要加入的查询字符串，array_merge将它们连接在一起，并http_build_query 3}}为我们创建新的组合字符串。

// Parse the URL into components
$url = 'http://...';
$url_parsed = parse_url($url);
$new_qs_parsed = array();
// Grab our first query string
parse_str($url_parsed['query'], $new_qs_parsed);
// Here's the other query string
$other_query_string = 'that=this&those=these';
$other_qs_parsed = array();
parse_str($other_query_string, $other_qs_parsed);
// Stitch the two query strings together
$final_query_string_array = array_merge($new_qs_parsed, $other_qs_parsed);
$final_query_string = http_build_query($final_query_string_array);
// Now, our final URL:
$new_url = $url_parsed['scheme'] 
         . '://'
         . $url_parsed['host'] 
         . $url_parsed['path'] 
         . '?'      
         . $final_query_string;

Answer 2

您可以使用以下命令从URL获取查询字符串部分：

$_SERVER['QUERY_STRING']

然后正常将其附加到网址。

如果要在查询字符串中指定自己的自定义变量，请查看：

<强> http_build_query

Answer 3

这是一系列从WordPress“框架”中获取的功能，但这可能会太多了：

<强> add_query_arg（）

/**
 * Retrieve a modified URL query string.
 *
 * You can rebuild the URL and append a new query variable to the URL query by
 * using this function. You can also retrieve the full URL with query data.
 *
 * Adding a single key & value or an associative array. Setting a key value to
 * emptystring removes the key. Omitting oldquery_or_uri uses the $_SERVER
 * value.
 *
 * @since 1.0
 *
 * @param mixed $param1 Either newkey or an associative_array
 * @param mixed $param2 Either newvalue or oldquery or uri
 * @param mixed $param3 Optional. Old query or uri
 * @return string New URL query string.
 */
public function add_query_arg() {
    $ret = '';
    if ( is_array( func_get_arg(0) ) ) {
        $uri = ( @func_num_args() < 2 || false === @func_get_arg( 1 ) ) ? $_SERVER['REQUEST_URI'] : @func_get_arg( 1 );
    } else {
        $uri = ( @func_num_args() < 3 || false === @func_get_arg( 2 ) ) ? $_SERVER['REQUEST_URI'] : @func_get_arg( 2 );
    }

    if ( $frag = strstr( $uri, '#' ) ) {
        $uri = substr( $uri, 0, -strlen( $frag ) );
    } else {
        $frag = '';
    }

    if ( preg_match( '|^https?://|i', $uri, $matches ) ) {
        $protocol = $matches[0];
        $uri = substr( $uri, strlen( $protocol ) );
    } else {
        $protocol = '';
    }

    if ( strpos( $uri, '?' ) !== false ) {
        $parts = explode( '?', $uri, 2 );
        if ( 1 == count( $parts ) ) {
            $base = '?';
            $query = $parts[0];
        } else {
            $base = $parts[0] . '?';
            $query = $parts[1];
        }
    } elseif ( !empty( $protocol ) || strpos( $uri, '=' ) === false ) {
        $base = $uri . '?';
        $query = '';
    } else {
        $base = '';
        $query = $uri;
    }

    parse_str( $query, $qs );

    if ( get_magic_quotes_gpc() )
        $qs = format::stripslashes_deep( $qs );

    $qs = format::urlencode_deep( $qs ); // this re-URL-encodes things that were already in the query string
    if ( is_array( func_get_arg( 0 ) ) ) {
        $kayvees = func_get_arg( 0 );
        $qs = array_merge( $qs, $kayvees );
    } else {
        $qs[func_get_arg( 0 )] = func_get_arg( 1 );
    }

    foreach ( ( array ) $qs as $k => $v ) {
        if ( $v === false )
            unset( $qs[$k] );
    }

    $ret = http_build_query( $qs, '', '&' );
    $ret = trim( $ret, '?' );
    $ret = preg_replace( '#=(&|$)#', '$1', $ret );
    $ret = $protocol . $base . $ret . $frag;
    $ret = rtrim( $ret, '?' );
    return $ret;
}

<强> stripslashes_deep（）

/**
 * Navigates through an array and removes slashes from the values.
 *
 * If an array is passed, the array_map() function causes a callback to pass the
 * value back to the function. The slashes from this value will removed.
 *
 * @since 1.0
 *
 * @param array|string $value The array or string to be stripped
 * @return array|string Stripped array (or string in the callback).
 */
function stripslashes_deep( $value ) {
    return is_array( $value ) ? array_map( array('self', 'stripslashes_deep'), $value ) : stripslashes( $value );
}

<强> urlencode_deep（）

/**
 * Navigates through an array and encodes the values to be used in a URL.
 *
 * Uses a callback to pass the value of the array back to the function as a
 * string.
 *
 * @since 1.0
 *
 * @param array|string $value The array or string to be encoded.
 * @return array|string $value The encoded array (or string from the callback).
 */
public function urlencode_deep( $value ) {
    return is_array($value) ? array_map( array('self', 'urlencode_deep'), $value) : urlencode($value);
}

Answer 4

这样做没有内置功能。但是，您可以从http PECL扩展名

使用此功能

http://usphp.com/manual/en/function.http-build-url.php

例如，

$url = http_build_url("http://www.example.com/index.php/page?a=1",
    array(
        "b" => "2"
    )
);

Answer 5

那么如果网址冲突会发生什么？如果两个url在查询字符串中都包含b=组件？你需要决定哪个控制权。

这里有一大堆代码可以满足您的需求，将每个字符串解析为网址，然后提取query网址部分，并implode()将它们重新组合在一起。

$url="http://www.example.com/index.php/page?a=1";
$qs ="?b=2";

$url_parsed = parse_url($url);
$qs_parsed = parse_url($qs);

$args = array(
    $url_parsed['query'],
    $qs_parsed['query'],
);

$new_url = $url_parsed['scheme'];
$new_url .= '://';
$new_url .= $url_parsed['host'];
$new_url .= $url_parsed['path'];
$new_url .= '?';
$new_url .= implode('&', $args);

print $new_url;

如何在PHP中组合查询字符串

5 个答案: