Question

我需要使用sql语句的日期字符串，如..

select getDate()

这将返回2010-06-08 16:31:47.667

但我需要这种格式201006081631 = yyyymmddhoursmin

我怎么能得到这个？

由于

Answer 1

单程

select left(replace(replace(replace(
   convert(varchar(30),getDate(),120),' ',''),'-',''),':',''),12)

或者像这样

select replace(replace(replace(
   convert(varchar(16),getDate(),120),' ',''),'-',''),':','')

或

select convert(varchar(8), getdate(),112) + 
   (replace(convert(varchar(5), getdate(),108),':',''))

另请参阅：CAST and CONVERT (Transact-SQL)

Answer 2

另一种方式......

DECLARE @d DATETIME

SELECT @d = '2010-06-09 1:37:58.030'


Select Convert(BigInt, 100000000) * Year(@d)
        + Month(@d) * 1000000
        + Day(@d) * 10000
        + DatePart(Hour, @d) * 100
        + DatePart(Minute, @d)

此处返回的数据类型是BigInt。

Answer 3

使用DATEPART：

SELECT CAST(DATEPART(yyyy, x.dt) AS VARCHAR(4)) + 
       CASE WHEN DATEPART(mm, x.dt) < 10 THEN '0'+ CAST(DATEPART(mm, x.dt) AS VARCHAR(1)) ELSE CAST(DATEPART(mm, x.dt) AS VARCHAR(2)) END +
       CASE WHEN DATEPART(dd, x.dt) < 10 THEN '0'+ CAST(DATEPART(dd, x.dt) AS VARCHAR(1)) ELSE CAST(DATEPART(dd, x.dt) AS VARCHAR(2)) END +
       CASE WHEN DATEPART(hh, x.dt) < 10 THEN '0'+ CAST(DATEPART(hh, x.dt) AS VARCHAR(1)) ELSE CAST(DATEPART(hh, x.dt) AS VARCHAR(2)) END +
       CASE WHEN DATEPART(mi, x.dt) < 10 THEN '0'+ CAST(DATEPART(mi, x.dt) AS VARCHAR(1)) ELSE CAST(DATEPART(mi, x.dt) AS VARCHAR(2)) END 
  FROM (SELECT '2010-06-08 16:31:47.667' dt) x

对于SQL Server 2005+，我会考虑创建一个日期格式的CLR函数 - C＃DateTime.ToString() supports providing a more normal means of formatting the date。

从getdate方法获取日期字符串

3 个答案: