我的代码需要一些帮助,我在数组中存储了字符串列表,当我尝试打印字符串列表时,当我在循环中使用变量时,它不会让我打印它们
pos_start = list()
pos_top = list()
pos_width = list()
pos_height = list()
prog_title = list()
for ind, row in enumerate(programs):
programs_top = 315
program_height = 33
program_gap = 3
position_start = start_pos
position_top = programs_top + channel_index * (program_height + program_gap + 1.5)
#create width size for per program button
if program_length >= 10 and program_length <= 45: #30 mins
program_width = 342
pos_start.append(position_start)
pos_top.append(position_top)
pos_width.append(program_width)
pos_height.append(program_height)
position_start = map(str, pos_start)
position_top = map(str, pos_top)
program_width = map(str, pos_width)
program_height = map(str, pos_height)
program_title = map(str, prog_title)
for position_start, position_width, position_height, program_title in zip(pos_start, pos_width, pos_height, prog_title):
print position_start
这是position_start的输出:
13:41:23 T:4812 NOTICE: ['375', '1073', '1771', '2120', '2469', '2818', '3167', '3516',
'3865', '4563', '5261', '5959', '6657', '7355', '7704', '8053', '8402', '8751', '9100', '9449',
'9798', '10147', '10496', '10845', '11543', '12241', '12939', '13288', '13637', '13986', '14335',
'15033', '15731', '16080', '16429', '16778', '17127', '17476', '17825', '18174', '18523', '18872',
'19221', '19570', '19919', '20268', '20617', '20966', '21315', '21664', '22013', '22362', '22711',
'23060', '23409', '23758', '24107', '24456', '24805', '25154', '25503', '25852', '26201', '26550',
'26899', '27248', '27597', '28295', '28993']
我可以在for循环之外使用print position_start
。
你能告诉我如何打印我想从数组中读取字符串的每个字符串吗?
我尝试使用for position_start, position_width, position_height, program_title in zip(pos_start, pos_width, pos_height, prog_title):
打印每个字符串,但它不会让我。
有什么想法吗?
答案 0 :(得分:2)
for item in position_start:
print item
如果它们的长度相同(并且我不建议使用并行数组,因为它们很容易成为一个项目),您可以执行以下操作:
for i in range(0, len(position_start)):
print position_start[i]
print position_top[i]
print program_width[i]
print program_heigh[i]
print program_title[i]
你也可以像试图获取元组列表那样压缩它们。这适用于均匀或不均匀的列表。这是一个例子:
import itertools
l1 = [1, 2, 3]
l2 = [4, 5, 6, 7]
listZipped = itertools.izip_longest(l1, l2)
for item in listZipped:
print item