我使用了自举开关切换开关按钮。
如果我在谷歌表格表中使用它,它运行正常。但它显示了谷歌桌面内的简单复选框。
<html>
<head>
<meta charset="UTF-8">
<title>Alerts</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css">
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js"></script>
<link href="https://gitcdn.github.io/bootstrap-toggle/2.2.0/css/bootstrap-toggle.min.css" rel="stylesheet">
<script src="https://gitcdn.github.io/bootstrap-toggle/2.2.0/js/bootstrap-toggle.min.js"></script>
<script type='text/javascript' src='https://www.google.com/jsapi'></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type='text/javascript' src='https://www.google.com/jsapi'></script>
</head>
<script type='text/javascript'>
google.load('visualization', '1', {packages:['table'], "callback": drawTable});
function drawTable() {
var data = new google.visualization.DataTable();
data.addColumn('string', 'Report');
data.addColumn('string', '');
data.setColumnProperty(1, {allowHtml: true});
data.addRows([
["aaaa",'<input id ="toggle" class="toggle" data-toggle="toggle" type = "checkbox" data-width="100" />'],
["dddd",'<input id="toogle" data-toggle="toggle" type="checkbox" data-width="100"/>'],
]);
options = {showRowNumber: true,'height':250,}
var table = new google.visualization.Table(document.getElementById('chart_div1'));
table.draw(data, {showRowNumber: true, allowHtml: true, page:'enable', pageSize:8});
$('.toggle').bootstrapToggle('toggle');
};
</script>
<body>
<div class = "chart_div1" id = "chart_div1"></div>
<input id="toogle" data-toggle="toggle" type="checkbox" data-width="100"/>
</body>
</html>
请给我一个解决方案,
先谢谢。
答案 0 :(得分:0)
删除第16行
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>