在python

Question

我是python和编程的新手！

我需要编写一个包含4个元组的程序，每个元素包含5个元素。一个元组应该有动词，一个元组应该有名词，一个元组应该有形容词，一个元组应该有副词。然后我必须使用0到4之间随机生成的数字来从每个元组中选择一个元素。这就是我到目前为止所做的：

import random

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")
num = random.randrange(0,5)
print (num)

有人能告诉我我做错了吗？

Answer 1

您可以在列表推导中使用random.choice，然后将所选列表与join连接起来：

>>> l=[nouns,verbs,adj,adv]
>>> ' '.join([random.choice(i) for i in l])
'girl runs dirty crazily.'
>>> ' '.join([random.choice(i) for i in l])
'monkey hits clueless occasionally.'

Answer 2

您理解的最简单方法：

import random

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")
num = random.randrange(0,5)
print nouns[num] + ' ' + verbs[num] + ' ' + adv[num] + ' ' + adj[num]

Answer 3

对于类似于已接受答案的函数，该函数返回所有可能的排列：

import random

def make_random_sentence():
  nouns = ["puppy", "car", "rabbit", "girl", "monkey"]
  verbs = ["runs", "hits", "jumps", "drives", "barfs"]
  adv = ["crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally."]
  adj = ["adorable", "clueless", "dirty", "odd", "stupid"]

  random_entry = lambda x: x[random.randrange(len(x))]
  return " ".join([random_entry(nouns), random_entry(verbs), random_entry(adv), random_entry(adj)])

Answer 4

如果你想为每个tupple选择总是相同的索引，那么尝试这样的事情：

import random
idx = random.randrange(0, 5)
print ("%s %s %s %s"%(nouns[idx], verbs[idx], adv[idx], adj[idx]))

如果您想获得每个tupple的随机元素，以下内容应该有效：

import random
print("%s %s %s %s"%(random.choice(nouns), random.choice(verbs), random.choice(adv), random.choice(adj))

Answer 5

num = random.randrange(0,5)   
print (num)

只需提供您生成的随机数。您需要使用您生成的随机数来访问元组。

print(nouns[num])
print(verbs[num])
print(adv[num])
print(adj[num])

Answer 6

我会使用random.choice执行以下操作，因为它比random.randrange更好...

words = (adj, nouns, verb, adv)
sentence = "".join(choice(word) for word in words)

Answer 7

random.choice 是从列表、元组或类似容器中随机选择一个事物。 最后一行的作用是从每个列表中随机选择一个事物，并从选择中创建一个新列表。然后打印该列表。在循环中，无论用户输入什么数字，都会执行 X 次。

from random import choice 

nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")

# asking user as to how many sentences he would like to generate 
for _ in range (int (input ("Enter integer value :"))): 
    print(list(map(choice, [nouns, verbs, adv, adj])))

Enter integer value :2
['car', 'barfs', 'dutifully.', 'odd']
['rabbit', 'runs', 'occasionally.', 'clueless']

[Program finished] 

Answer 8

import random
nouns = ("puppy", "car", "rabbit", "girl", "monkey")
verbs = ("runs", "hits", "jumps", "drives", "barfs") 
adv = ("crazily.", "dutifully.", "foolishly.", "merrily.", "occasionally.")
adj = ("adorable", "clueless", "dirty", "odd", "stupid")
num = random.randrange(0,5)
print(nouns[num],verbs[num],adv[num],adj[num])