Question

这究竟是做什么的？

var counts = new Dictionary<string, int>();
for (int i = 0; i < 10; i++)
counts[string.Format("STA Thread Queue Worker Thread No. {0}", i + 1)] = 0;

由于

Answer 1

它填充了一个包含10个元素的字典：

Key                                     | Value
----------------------------------------|------
"STA Thread Queue Worker Thread No. 1"  | 0
"STA Thread Queue Worker Thread No. 2"  | 0
"STA Thread Queue Worker Thread No. 3"  | 0
"STA Thread Queue Worker Thread No. 4"  | 0
"STA Thread Queue Worker Thread No. 5"  | 0
"STA Thread Queue Worker Thread No. 6"  | 0
"STA Thread Queue Worker Thread No. 7"  | 0
"STA Thread Queue Worker Thread No. 8"  | 0
"STA Thread Queue Worker Thread No. 9"  | 0
"STA Thread Queue Worker Thread No. 10" | 0

Answer 2

它创建一个字典，其中包含10个条目：

条目：值

"STA Thread Queue Worker Thread No. 1" : 0
"STA Thread Queue Worker Thread No. 2" : 0
"STA Thread Queue Worker Thread No. 3" : 0
"STA Thread Queue Worker Thread No. 4" : 0
"STA Thread Queue Worker Thread No. 5" : 0
"STA Thread Queue Worker Thread No. 6" : 0
"STA Thread Queue Worker Thread No. 7" : 0
"STA Thread Queue Worker Thread No. 8" : 0
"STA Thread Queue Worker Thread No. 9" : 0
"STA Thread Queue Worker Thread No. 10" : 0

更具体地说：

var counts = new Dictionary<string, int>();

在名为counts的字段中创建字典。 var表示推断出类型。

for (int i = 0; i < 10; i++)

循环从0到9（含）

counts[string.Format("STA Thread Queue Worker Thread No. {0}", i + 1)] = 0;

使用该行代码生成的密钥为该字段分配0。

string.Format("STA Thread Queue Worker Thread No. {0}", i + 1)

生成一个字符串，将传递给Format方法的第二个参数分配到标有{0}的字符串的位置。例如

string.format("{0} {1} {2}", "foo", "bar" "bash")

创建：

"foo bar bash"

Answer 3

第一行将创建一个新的Dictionary，其中字符串为键，int为这些键的值，
它就像一个Hash Table。

第二行将执行第三行10次，i从0到9。

在第三行中，我们将字符串中的字符串与其值一起存储，以便可以快速查找，字符串包含i + 1，即1到10，并将其对应的值设置为0。

STA Thread Queue Worker Thread No. 1 --> 0  
STA Thread Queue Worker Thread No. 2 --> 0  
...

提示：最好为此使用一个数组，不需要散列字符串，因为它们是静态的，除了整数。因此，字符串可以在以后需要时连接。

var counts = new int[10];
for (int i = 0; i < 10; i++)
    counts[i] = 0;

甚至更短，因为默认情况下元素为0：

var counts = new int[10];

Answer 4

它创建一个字典（一个包含字符串键和整数值的查找表）并初始化它，以便它保存以下数据：

key  =>  value
STA Thread Queue Worker Thread No. 1 => 0
STA Thread Queue Worker Thread No. 2 => 0
STA Thread Queue Worker Thread No. 3 => 0
STA Thread Queue Worker Thread No. 4 => 0
STA Thread Queue Worker Thread No. 5 => 0
...
STA Thread Queue Worker Thread No. 10 => 0

因此，对于每个10个工作线程（在此代码中未创建或操作），您将获得存储在字典中的值0。

Answer 5

这将创建一个Dictionary<string, int>，并将其初始化为10个条目，这些条目都设置为0，其键入为：

STA Thread Queue Worker Thread No. 1
STA Thread Queue Worker Thread No. 2
...
STA Thread Queue Worker Thread No. 10

Answer 6

只是猜测，但它看起来像是用来初始化一个字典的部分代码，供10个工作线程用来存储计算结果。

可能缺少代码下方某处实际产生十个不同的线程写入相应的"STA Thread Queue Worker Thread No. {0}"密钥。线程完成后，可以聚合值。

嗯，相当（但不是正式）线程安全，但如果我猜错了，简单的var counts = new int[10]会更好。

C＃代码行

6 个答案: