Question

我有一个select查询绑定到具有特定ORDER BY CASE语句的数据集。查询功能正常并返回正确的数据，但主键Ordnum的顺序每次在CASE语句中排序不同。对此查询的任何编辑都会使排序保持一致？查询是：

SELECT Ordnum, BrwrFstNme, BrwrLastNme, PrpAddr, PrpCity, PrpSt, PrpZip5, PrpCntyNme, errorCategory, errorReason, errorReason2, userName, priority, 
                     completed, timeAssigned, timeCompleted, notes, flag, week, process, ignoreGISScoreCard, currentMonth, currentYear, currentDay, currentDOY, OrdDTE, sfha

FROM qc_Orders WHERE (userName = @usrnme) AND (completed IS NULL) AND (week = (SELECT TOP (1) QCTrack FROM CloneOrders ORDER BY QCTrack DESC))
ORDER BY 
(CASE WHEN process = 'Manual' AND notes LIKE '%wells%' THEN '1'
WHEN process IN ('883', '885', '886', '887', '900', '901', '902') AND notes LIKE '%wells%' THEN '2'
WHEN (process = '888' OR process LIKE '889%') AND notes  LIKE '%wells%' THEN '3'
WHEN process = 'Manual' AND (notes NOT LIKE '%wells%' or notes IS NULL) THEN '4'
WHEN process IN ('883', '885', '886', '887', '900', '901', '902') AND (notes NOT LIKE '%wells%' or notes IS NULL) THEN '5'
ELSE process END) ASC

修改

我确实需要在tiebreaker声明中加入Order By Case。我还创建了更多CASE语句，但简化了result_expression。添加Ordnum作为最终条款消除了每个CASE内的随机排序。最终查询如下：

SELECT Ordnum, BrwrFstNme, BrwrLastNme, PrpAddr, PrpCity, PrpSt, PrpZip5, PrpCntyNme, errorCategory, errorReason, errorReason2, userName, priority, 
                     completed, timeAssigned, timeCompleted, notes, flag, week, process, ignoreGISScoreCard, currentMonth, currentYear, currentDay, currentDOY, OrdDTE, sfha

FROM qc_Orders WHERE (userName = @usrnme) AND (completed IS NULL) AND (week = (SELECT TOP (1) QCTrack FROM CloneOrders ORDER BY QCTrack DESC))
ORDER BY 
CASE WHEN NOTES LIKE '%WELLS%' THEN 1 END DESC,
CASE WHEN PROCESS = 'MANUAL' THEN 1 END DESC,
CASE WHEN PROCESS IN ('883', '885', '886', '887', '900', '901', '902') THEN 1 END DESC,
CASE WHEN PROCESS = '888' THEN 1 END DESC,
CASE WHEN PROCESS LIKE '889%' THEN 1 END DESC,
CASE WHEN NOTES LIKE '%WELLS%' THEN 2 END DESC,
CASE WHEN PROCESS = 'MANUAL' THEN 2 END DESC,
CASE WHEN PROCESS IN ('883', '885', '886', '887', '900', '901', '902') THEN 2 END DESC,
CASE WHEN PROCESS = '888' THEN 2 END DESC, 
CASE WHEN PROCESS LIKE '889%' THEN 2 END DESC,
ORDNUM ASC

Answer 1

您应在tiebreaker子句中添加ORDER。如果Ordnum中的CASE是唯一的，请在CASE之后添加ORDER。如果没有，那么您将不得不在SELECT Ordnum, BrwrFstNme, BrwrLastNme, PrpAddr, PrpCity, PrpSt, PrpZip5, PrpCntyNme, errorCategory, errorReason, errorReason2, userName, priority, completed, timeAssigned, timeCompleted, notes, flag, week, process, ignoreGISScoreCard, currentMonth, currentYear, currentDay, currentDOY, OrdDTE, sfha FROM qc_Orders WHERE (userName = @usrnme) AND (completed IS NULL) AND (week = (SELECT TOP (1) QCTrack FROM CloneOrders ORDER BY QCTrack DESC)) ORDER BY (CASE WHEN process = 'Manual' AND notes LIKE '%wells%' THEN '1' WHEN process IN ('883', '885', '886', '887', '900', '901', '902') AND notes LIKE '%wells%' THEN '2' WHEN (process = '888' OR process LIKE '889%') AND notes LIKE '%wells%' THEN '3' WHEN process = 'Manual' AND (notes NOT LIKE '%wells%' or notes IS NULL) THEN '4' WHEN process IN ('883', '885', '886', '887', '900', '901', '902') AND (notes NOT LIKE '%wells%' or notes IS NULL) THEN '5' ELSE process END) ASC, Ordnum子句中添加更多列：

accountManager.getAccounts()

查询在刷新时排序不同

1 个答案: