Question

我必须以（mm / dd / yyyy）形式输入日期。所以，在报告这个日期时，我会有类似于05/13/1999的内容，如何从月份中删除零。我希望它能够读取像11/12/1999那样的两位数月份

from functionax import disp_bday
name = raw_input("Enter name: ")
s = date = raw_input("Enter dob (mm/dd/yyyy): ")
x = month = int((s[0:1])             
year = s[6:10]
print disp_bday(name, month, year)

functionax低于

from datetime import date


def display_birthday_wishes(name, month, year):
    p = current_year = date.today().year
    current_age = (int(p)-int(year))
    if month == 1:
        month = 'Carnations'
    elif month == 2:
        month = 'Primroses'
    elif month == 3:
        month = 'Daffodils'
    elif month == 4:
        month = 'Sweet peas'
    elif month == 5:
        month = 'Hawthorn flowers'
    elif month == 6:
        month = 'Roses'
    elif month == 7:
        month = 'Water lilies'
    elif month == 8:
        month = 'Poppies'
    elif month == 9:
        month = 'Asters'
    elif month == 10:
        month = 'Calendulas'
    elif month == 11:
        month = 'Chrysanthemums'
    elif month == 12:
        month = 'Holly flowers'    

    return "Hi, " + name + ". You are " + str(current_age) +\
    " years old this year! Here's a bouquet of "+month+" for you!"

Answer 1

这听起来好像你想使用Regular Expression：

import re

m = re.match(r'(\d{1,2})/(\d{1,2})/(\d{4})', date)
if m:
    print disp_bday(m.groups())
else:
    print "invalid input"

有关使用的表达式

的更多信息，请查看here

Answer 2

您在第4行缺少右括号。

你可以这样做：

from datetime import date

flowers = [
    'Carnations',
    'Primroses',
    'Daffodils',
    'Sweet peas',
    'Hawthorn flowers',
    'Roses',
    'Water lilies',
    'Poppies',
    'Asters',
    'Calendulas',
    'Chrysanthemums',
    'Holly flowers'
    ]

def display_birthday_wishes(name, month, year):
    p = date.today().year
    current_age = (int(p)-int(year))
    return "Hi, " + name + ". You are " + str(current_age) +\
    " years old this year! Here's a bouquet of "+ flowers[month-1] +" for you!"

name = raw_input("Enter name: ")
foo = raw_input("Enter dob (mm/dd/yyyy): ")
month, d, year = foo.split("/")
if month[0] == "0":
    month = int(month[1:])
print display_birthday_wishes(name, month, year)

请注意，我必须修改前面的示例，以便不提date（我只是将该变量缩短为d），否则它会干扰date函数。

Answer 3

不要自己解析状态，而是使用内置的datetime模块

>>> dt = datetime.strptime("05/13/1999", "%m/%d/%Y")
>>> dt.month
5
>>> dt = datetime.strptime("11/12/1999", "%m/%d/%Y")
>>> dt.month
11

所以，只需替换代码

x = month = int((s[0:1])             
year = s[6:10]

到

dt = datetime.strptime(date , "%m/%d/%Y")
x = month = dt.month
year = dt.year

Answer 4

我没有在python2中试过这个，但是如果你使用的是python3

from datetime import date, datetime as dt

day, month, year = "05/13/1999".split("/")
old_date = date(int(year), int(day), int(month))
new_date = dt.strftime(old_date, "{0}/{1}/{2}".format(old_date.month, \
old_date.day, old_date.year))

Answer 5

在要剥离0的项目之前添加-。

datetime.strptime("05/13/1999", "%m/%d/%Y").strftime("%-m/%d/%Y")

删除日期中的前导零

5 个答案: