Question

我为两张桌子创建了模型。现在，我想执行查询并根据created_at合并结果。

我的疑问是：

    $first  =  RequestF::where('userId','=',$userId)->get();
    $second =  RequestS::where('userId','=',$userId)->get();

我可以使用以下方法合并它们：

     foreach($first as $f) {
        $second->add($f);
     }

但这只会在$first末尾添加$second - 对象，我无法按照created_at的顺序获取它们。

如何合并这两个查询并同时订购？谢谢。

更新在@MargusPala建议之后，这是$second->toArray()之后的结果，但奇怪的是一个对象没有按顺序排列!!对象编号10：

{
  "status" : "Success",
  "data" : {
"showcases" : {
  "10" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-22 10:51:25",
    "type" : "F"
  },
  "2" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-23 10:14:32",
    "type" : "L"
  },
  "3" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-23 10:15:00",
    "type" : "L"
  },
  "11" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-27 09:54:56",
    "type" : "F"
  },
  "4" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-23 11:22:09",
    "type" : "L"
  },
  "5" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-26 10:42:38",
    "type" : "L"
  },
  "6" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-27 09:59:03",
    "type" : "L"
  },
  "7" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-27 09:59:23",
    "type" : "L"
  },
  "0" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-22 11:26:25",
    "type" : "L"
  },
  "8" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-27 10:05:19",
    "type" : "L"
  },
  "1" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-23 10:13:53",
    "type" : "L"
  },
  "9" : {
    "userName" : "mojtaba_talebii",
    "created_at" : "2015-04-27 10:05:33",
    "type" : "L"
  }
}
  },
 "message" : "Here is results"
}

这很奇怪，还有其他什么，我怎么能得到结果屁股JSON数组，而不是JSON对象。

Answer 1

Laravel具有sortBy（）函数，允许您对集合进行排序。像这样使用它

$second = $second->sortBy(function($s)
{
    return $s->created_at;
});

合并两个查询并在Laravel中基于created_at对它们进行排序

1 个答案: