我只是创建一个模块。添加值后得到问题IndexError:列表赋值索引超出范围。如何解决它。请重新编辑代码。 这是我的代码:
class calculator(osv.osv):
_name = 'calculator.calculator'
def get_total(self, cr, uid, ids, field_name, arg, context):
res = []
perfos = self.browse(cr, uid, ids, context)
for perfo in perfos:
res[perfo.id] = perfo.p + perfo.b
return res
_columns = {
'p':fields.selection(((1,'Outstanding'), (2,'Well Above Expectations'), (3,'As Expected'), (4,'Below Expectations'), (5,'VeryPoor'), (0,'N/A')),'title'),
'b':fields.selection(((1,'Outstanding'), (2,'Well Above Expectations'), (3,'As Expected'), (4,'Below Expectations'), (5,'Very Poor'), (0,'N/A')),'title'),
'total' : fields.function(get_total, method=True, string='Total Mark'),
}
答案 0 :(得分:2)
您需要返回功能字段的字典字典。您将res
定义为列表,并尝试将其指定为字典。 res[perfo.id]
被视为列表,perfo.id
列表中未找到索引值res
。这就是错误所说的。现在代码将是
class calculator(osv.osv):
_name = 'calculator.calculator'
def get_total(self, cr, uid, ids, field_name, arg, context):
res = {}
for perfos in self.browse(cr, uid, ids, context):
res[perfos.id] = perfos.p + perfos.b
return res
_columns = {
'p':fields.selection(((1,'Outstanding'), (2,'Well Above Expectations'), (3,'As Expected'), (4,'Below Expectations'), (5,'VeryPoor'), (0,'N/A')),'title'),
'b':fields.selection(((1,'Outstanding'), (2,'Well Above Expectations'), (3,'As Expected'), (4,'Below Expectations'), (5,'Very Poor'), (0,'N/A')),'title'),
'total' : fields.function(get_total, method=True, string='Total Mark'),
}
对于上面的代码,您可能会收到此js错误Error: [_.sprintf] expecting number but found string
我没有得到两个选择字段。密钥将以unicode格式加1 + 1。
以下代码将为您提供功能字段的基本概念。
class calculator(osv.osv):
_name = 'calculator.calculator'
def get_total(self, cr, uid, ids, field_name, arg, context):
res = {}
for perfos in self.browse(cr, uid, ids, context):
res[perfos.id] = perfos.p + perfos.b
return res
_columns = {
'p':fields.integer('A'),
'b':fields.integer('B'),
'total' : fields.function(get_total, method=True, string='Total Mark'),
}
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