Question

我们有一个包含三列（public partial class Form1 : Form { List<Product> source; public Form1() { InitializeComponent(); } private void Form1_Load(object sender, EventArgs e) { source = new List<Product>(); } private void button1_Click(object sender, EventArgs e) { decimal price; if (string.IsNullOrEmpty(txtProduct.Text) || !decimal.TryParse(txtPrice.Text, out price)) { MessageBox.Show("Invalid values!"); return; } var existingProduct = source.Where(x=> x.ProductName==txtProduct.Text).SingleOrDefault(); if(existingProduct!=null) { existingProduct.Price += price; } else source.Add(new Product {Price = price, ProductName = txtProduct.Text} ); listBox1.DataSource = null; listBox1.DataSource = source; } } public class Product { public string ProductName { get; set; } public decimal Price { get; set; } public override string ToString() { return string.Format("{0} = {1}", ProductName, Price.ToString("c")); } }，Name_of_office，Month）的表格，如下所示：

Amount

应使用财政年度月计算。

通过公式总是从4月开始到选定的月份。

假设用户将选择6月（从下拉列表）

计算应该像这样进行

Name_Of_Office      Month     Amount
------------------------------------
DivisionBhopal      04         125
DivisionBhopal      05          50
DivisionBhopal      06         100
DivisionBhopal      10         125
DivisionSagar       04         600
DivisionSagar       05         520
DivisionSagar       06         400
DivisionSagar       10         100

这里我们不会添加oct金额，因为选择的月份是6月我们想要数据到6月

6月份，数据应如下所示：

Name_Of_Office     Sum Upto Previous Month    Present Month   Total Amount
-----------------------------------------------------------------------------------------
DivisionBhopa      April + May                June            April + May+ June 
DivisionSagar      April  + May               June            April + May+ June

10月的数据应该是（如果用户选择12月）：

Name_Of_Office     Sum Upto Previous Month   Present Month    Total  Amount
---------------------------------------------------------------------------
DivisionBhopal           175                     100              275
DivisionSagar           1120                     400             1520

Answer 1

你可以试试吗

    SELECT A.NAME_OF_OFFICE, B.SUM_UPTO_PREV_MONTH, A.AMOUNT,B.SUM_UPTO_CURR_MONTH
FROM TEMP A
INNER JOIN 
(
SELECT NAME_OF_OFFICE, SUM(AMOUNT) SUM_UPTO_PREV_MONTH
FROM  TEMP
GROUP BY NAME_OF_OFFICE
WHERE MONTH < 6
) B ON A.NAME_OF_OFFICE = B.NAME_OF_OFFICE
INNER JOIN
(
SELECT NAME_OF_OFFICE, SUM(AMOUNT) SUM_UPTO_CURR_MONTH
FROM  TEMP
GROUP BY NAME_OF_OFFICE
WHERE MONTH <= 6
) C ON A.NAME_OF_OFFICE = C.NAME_OF_OFFICE
WHERE A.MONTH = 6

Answer 2

您可以使用条件聚合：

select office,
sum(amount)as total,
sum(case when month = @passedmonth then amount else 0 end) as present,
sum(case when month < @passedmonth then amount else 0 end) as prev
from table
where month >= 4 and month < @passedmonth
group by office

编写Sql查询

2 个答案: