我有这样的json数据:
{"Adobe Photoshop":"70","Adobe Premier":"71","Animasyon":"72","AutoCAD":"73","Bro\u015f\u00fcr & Bilet":"75","CorelDraw":"76","Flash":"77","Grafik Tasar\u0131m":"68","Karikat\u00fcr":"78","Kartvizit Tasar\u0131m":"79","Logo Tasar\u0131m":"80","Poster":"81","Reklam Tasar\u0131m":"74","Ses D\u00fczenleme":"82","Video D\u00fczenleme":"69","Web Tasar\u0131m":"83"}
首先想想(Adobe Photoshop)意味着标签名称,第二件事(70)意味着标签ID。我想在jquery like array中使用这些信息来为每个标记构建复选框。我怎么能这样做?感谢
答案 0 :(得分:3)
您正在寻找for in
循环,如下所示:
for(var key in something) {
if (!something.hasOwnProperty(key)) continue; //Skip inherited members
var value = something[key];
//Do things...
}
请注意,未定义迭代顺序。
答案 1 :(得分:1)
您需要for...in声明:
var i;
for (i in hash) {
doSomething(i, hash[i]);
}
答案 2 :(得分:1)
这样的东西?
var data = {"Adobe Photoshop":"70","Adobe Premier":"71","Animasyon":"72","AutoCAD":"73","Bro\u015f\u00fcr & Bilet":"75","CorelDraw":"76","Flash":"77","Grafik Tasar\u0131m":"68","Karikat\u00fcr":"78","Kartvizit Tasar\u0131m":"79","Logo Tasar\u0131m":"80","Poster":"81","Reklam Tasar\u0131m":"74","Ses D\u00fczenleme":"82","Video D\u00fczenleme":"69","Web Tasar\u0131m":"83"};
var $div = $('<div/>');
for(var name in data) {
$('<input/>',{ type:"checkbox", value:data[name] }).appendTo($div);
$('<label/>',{ text:name }).appendTo($div);
$('<br/>').appendTo($div);
}
$div.appendTo('body');