Question

我想根据[plan]和[order_id]值显示一列数据[pin]。 plan = 9，order_id = 0。想要在不重新加载页面的情况下加载数据，使用ajax。

这是我的HTML /脚本：

<script>
function showPins(str) {
if (str == "") {
document.getElementById("txtHint").innerHTML = "";
return;
} else {
if (window.XMLHttpRequest) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById("txtHint").innerHTML = xmlhttp.responseText;
}
}
xmlhttp.open("GET","getPins.php?q="+str,true);
xmlhttp.send();
}
}
</script>

HTML:
    <div align="center">
    <h3>View PIN's</h3>
    <form>
    <select name="users" onchange="showPins(this.value)">
      <option value="">Select Plan Type:</option>
      <option value="1">Plan1</option>
      <option value="2">Plan2</option>
      <option value="3">Plan3</option>  
    </select>
    </form>
    <br/>
    <div id="txtHint"></div>
    </div>

这是我的PHP文件（getPins.php）：

<?php
$q = intval($_GET['q']);

$con = mysqli_connect('myHost','myUsername','myPw','my_db');
if (!$con) {
    die('Could not connect: ' . mysqli_error($con));
}

mysqli_select_db($con,"my_db");
$sql="SELECT * FROM attPins WHERE (order_id=0, plan=9 and id = '".$q."')";
$result = mysqli_query($con,$sql);

echo "<table>
<tr>
<th>PIN's</th>
</tr>";
while($row = mysqli_fetch_array($result)) {
    echo "<tr>";    
    echo "<td>" . $row['pin'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysqli_close($con);

这是基于此处显示的教程：http://www.w3schools.com/php/php_ajax_database.asp

尝试使其显示所选计划类型的正确引脚。

Answer 1

您的查询错误阅读手册where

appellant_respondent = %x(sed -n '/assessment year/I{ :loop; n; /respondent/Iq; p; b loop}' #{@file_name}).split("\n")
appellant_name_array = []
respondent_name_array = []
appellant_respondent.delete("")
appellant_respondent.each do |names|
   names_array = names.split(/\s+\s+/)
   appellant_name_array << names_array.first if names_array.first != ""
   respondent_name_array << names_array.last if names_array.last != ""
end
@item[:appellant] = appellant_name_array.join(' ').gsub(/\s+vs\.*\s+/i, ' ').strip
@item[:respondent] = respondent_name_array.join(' ').gsub(/\s+vs\.*\s+/i, ' ').strip

这将是

  $sql="SELECT * FROM attPins WHERE (order_id=0, plan=9 and id = '".$q."')";

或者

 WHERE (order_id=0 and plan=9 and id = '".$q."')

根据您的要求

使用AJAX，PHP和MySQL来显示表数据

1 个答案: