我有一个带有SD盾牌和GSM盾牌的Arduino超级巨星。我正在尝试从SD卡上的文本文件向200个号码发送一个短信,但每次我尝试发送超过100个号码时,Arduino都会重新启动。当我尝试发送到70个号码时,它不会崩溃。我一次只读一个号码,所以我不明白这个问题。我是Arduino编程的新手。
请帮助我这是一场锦标赛。这是代码:
#include <avr/pgmspace.h>
#include <SPI.h>
#include <SD.h>
#include <GSM.h>
#define PINNUMBER ""
GSM gsmAccess;
GSM_SMS sms;
// GSM
boolean notConnected;
//char input;
//byte input2;
//char txtContent[200];
byte i = 1;
byte f = 0;
boolean sendit;
//char senderNumber[11];
const String stopp PROGMEM = "Stopp";
//SD
char numbers[11];
//char nmbr;
int l = 0;
//Optimizing
const char q PROGMEM = '\xe5'; // å
const char w PROGMEM = '\xe4'; // ä
const char e PROGMEM = '\xf6'; // ö
const char r PROGMEM = '\xc5'; // Å
const char t PROGMEM = '\xc4'; // Ä
const char y PROGMEM = '\xd6'; // Ö
void setup() {
// txtContent[0] = '\0';
i = 0;
pinMode(53, OUTPUT);
Serial.begin(115200);
// Serial.begin(4800);
Serial.println(F("Connecting to GSM..."));
notConnected = true;
while (notConnected) {
if (gsmAccess.begin(PINNUMBER) == GSM_READY) {
notConnected = false;
}
else {
Serial.println(F("Not Connected"));
delay(1000);
}
}
Serial.println(F("GSM Ready"));
if (!SD.begin(4)) {
Serial.println(F("Error with SD card"));
return;
}
Serial.println(F("SD Ready"));
delay(1000);
Serial.println(F("Write your sms and end it with * and press Send"));
Serial.flush();
}
void loop() {
char txtContent[300];
if (Serial.available() > 0 && !sendit) {
byte input2;
input2 = (int)Serial.read();
txtContent[i] = (char)input2;
if (txtContent[i] == '{') {
txtContent[i] = q;
}
else if (txtContent[i] == '}') {
txtContent[i] = w;
}
else if (txtContent[i] == '|') {
txtContent[i] = e;
}
else if (txtContent[i] == '[') {
txtContent[i] = r;
}
else if (txtContent[i] == ']') {
txtContent[i] = t;
}
else if (txtContent[i] == ';') {
txtContent[i] = y;
}
i++;
if (input2 == '*') {
// Remove the * from text.
for (int j = 0; j < sizeof(txtContent); j++) {
if (txtContent[j] == '*') {
txtContent[j] = '\0';
//Serial.println(txtContent);
}
}
sendit = true;
Serial.flush();
}
else {
sendit = false;
Serial.flush();
}
}
else if (sendit && txtContent[0] != '\0') {
int txtCount = 0;
// else if(sendit){
Serial.println(F("Sending please wait..."));
// Serial.flush();
File myFile;
myFile = SD.open("numbers.txt");
char input;
if (myFile) {
// if (myFile.available()) {
while(myFile.available()){
input = (char)myFile.read();
if (input == ',') {
sms.beginSMS(numbers);
sms.print(txtContent);
// sms.beginSMS("0704941025");
// sms.print("yo");
delay(30);
sms.endSMS();
delay(30);
Serial.println(numbers);
Serial.flush();
// Serial.flush();
for (int j = 0; j < sizeof(numbers); j++) {
if (numbers[i] != '\0') {
numbers[j] = '\0';
}
}
f = 0;
}
else {
numbers[f] = input;
f++;
}
}
myFile.close();
Serial.println(F("All texts have been sent."));
Serial.flush();
} else {
Serial.println(F("error opening numbers.txt"));
}
for (int j = 0; j < sizeof(txtContent); j++) { // Clear text
txtContent[j] = '\0';
}
i = 0;
sendit = false;
}
else {
// delay(1000);
if (sms.available()) {
char senderNumber[11];
sms.remoteNumber(senderNumber, 11);
if (sms.peek() == 'S') {
Serial.print(F("Detta nummer har skickat Stopp: "));
Serial.println(senderNumber);
}
sms.flush();
Serial.flush();
// sendit = false;
}
}
}
答案 0 :(得分:0)
Arduino对我来说是一个奇怪的理由,但如果这有点像C,那么我冒险说sizeof(numbers)
可能会返回44,因为你要求字节大小,这可能意味着你当numbers[43]
长度为11时,for循环将迭代到numbers[]
。请考虑改为:
for (int j = 0; j < sizeof(numbers)/sizeof(numbers[0]); j++) {
在此代码中检查数组大小的所有其他时间也是如此。
另外,请仔细检查您的文本文件,以确保它以您预期的格式编写:11个数字,然后是逗号,没有例外。您可能应该尝试在点击逗号前确定f
是否超过11位数,并在显示错误消息时“优雅地失败”。