Question

我正在将此sample（site）移植到jogl，但我注意到图像中的某些内容并不完美，地板上的一些人工制品和形状并不完全正方形，就像你一样可以看到（不关心颜色，变化），地板看起来也不好看：

enter image description here

因此我试图首先只渲染地板（如果你想尝试，非常简单，从100开始SQRT_BUILDING_COUNT - > 0）并且我已经有了第一个问题，它应该是一个基于两个三角形的正方形，但我只看到其中一个。

enter image description here

public float[] position = new float[3];
public byte[] color = new byte[4];
public float[] attrib0 = new float[4];
public float[] attrib1 = new float[4];
public float[] attrib2 = new float[4];
public float[] attrib3 = new float[4];
public float[] attrib4 = new float[4];
public float[] attrib5 = new float[4];
public float[] attrib6 = new float[4];

attrib0-6目前尚未使用

My VS inputs：

// Input attributes
layout(location=0) in vec4 iPos;
layout(location=1) in vec4 iColor;
layout(location=2) in PerMeshUniforms* bindlessPerMeshUniformsPtr;
layout(location=3) in vec4 iAttrib3;
layout(location=4) in vec4 iAttrib4;
layout(location=5) in vec4 iAttrib5;
layout(location=6) in vec4 iAttrib6;
layout(location=7) in vec4 iAttrib7;

我宣布iPos为vec3，所以我猜它会在VS中填充为vec4（iPos，1）

I transfer data to gpu：

    gl4.glNamedBufferData(vertexBuffer[0], Vertex.size() * vertices.size(),
            GLBuffers.newDirectFloatBuffer(verticesArray), GL4.GL_STATIC_DRAW);
    gl4.glNamedBufferData(indexBuffer[0], GLBuffers.SIZEOF_SHORT * indices.size(),
            GLBuffers.newDirectShortBuffer(indicesArray), GL4.GL_STATIC_DRAW);

然后在我渲染I call之前：

        gl4.glEnableVertexArrayAttrib(0, 0);
        gl4.glEnableVertexArrayAttrib(0, 1);

然后渲染，original code is：

    // Set up attribute 0 for the position (3 floats)
    glVertexArrayVertexAttribOffsetEXT(0, m_vertexBuffer, 0, 3, GL_FLOAT, GL_FALSE, sizeof(Vertex), Vertex::PositionOffset);

    // Set up attribute 1 for the color (4 unsigned bytes)
    glVertexArrayVertexAttribOffsetEXT(0, m_vertexBuffer, 1, 4, GL_UNSIGNED_BYTE, GL_TRUE, sizeof(Vertex), Vertex::ColorOffset);

I substituted it with：

        // Set up attribute 0 for the position (3 floats)
        gl4.glVertexArrayVertexBuffer(0, 0, vertexBuffer[0], Vertex.positionOffset,
                Vertex.size());
        gl4.glVertexArrayAttribFormat(0, 0, 3, GL4.GL_FLOAT, false, Vertex.size());

        // Set up attribute 1 for the color (4 unsigned bytes)
        gl4.glVertexArrayVertexBuffer(0, 1, vertexBuffer[0], Vertex.colorOffset,
                Vertex.size());
        gl4.glVertexArrayAttribFormat(0, 1, 4, GL4.GL_UNSIGNED_BYTE, true, Vertex.size());

And then I finish the render：

        // Reset state
        gl4.glDisableVertexArrayAttrib(0, 0);
        gl4.glDisableVertexArrayAttrib(0, 1);

我承认我之前从未使用过dsa，我总是使用GL3和普通的vbo，vao和ibo，绑定和取消绑定..

剔除。

那怎么了？

Answer 1

解决了，问题是我没有正确实现dsa

glEnableVertexAttribArray(vao, 0);
glEnableVertexAttribArray(vao, 1);

// Setup the formats
glVertexArrayAttribFormat(vao, 0, 3, GL_FLOAT, GL_FALSE, 0);
glVertexArrayAttribFormat(vao, 1, 2, GL_FLOAT, GL_FALSE, 0);

// Setup the buffer sources
glVertexArrayVertexBuffer(vao, 0, buffers[0], 0, 0); // Note the 2nd argument here is a 'binding index', not the attribute index
glVertexArrayVertexBuffer(vao, 1, buffers[1], 0, 0);

// Link them up
glVertexArrayAttribBinding(vao, 0, 0); // Associate attrib 0 (first 0) with binding 0 (second 0).
glVertexArrayAttribBinding(vao, 1, 1);

如果您已编制索引呈现

，请

加glVertexArrayElementBuffer

我无法正确呈现一个简单的索引数组

1 个答案: