我想问一下，为什么我无法刷新两个html表？只有1个？ Javascript代码有什么问题吗？我已经尝试声明2个变量，并试图为每个变量创建脚本，但仍然没有运气，我试图将变量名称更改为唯一变量，但仍然没有运气。我的完整代码如下：
<!-- SALES.HTML -->
<div class="col-sm-5 shadow">
<p>
<h3><center>Hyukies</center></h3>
<center>Catbalogan, City</center>
<center><span class="glyphicon glyphicon-time"></span> <?php include('time.php'); ?></center> <br />
<div id="transactions_left">
<?php include_once('salestable.php')?>
</div>
</p>
<div class="row">
<div class="col-sm-12"><b>
<p>
<?php include_once('sales_count.php')?>
<script>
var table = $("#salestableid");
var refresh = function() {
table.load("salestable.php", function() {
setTimeout(refresh, 1);
});
};
refresh();
var table1 = $("#sales_countid");
var refresh1 = function() {
table.load("sales_count.php", function() {
setTimeout(refresh1, 1);
});
};
refresh1();
</script>
<button type="button" class="btn btn-danger btn-md" data-toggle='modal' data-target='#cancel'>Cancel</a>
<button type="button" class="btn btn-warning btn-md" data-toggle='modal' data-target='#hold'>Hold</button>
<button type="button" class="btn btn-success btn-md pull-right" data-toggle='modal' data-target='#payment' >Payment</button>
<br /><br />
<center>Thank you and have a Nice day!</center>
</p>
</div>
</div>
</div>
<!-- End of Page SALES.HTML -->
<!-- SALESTABLE.PHP -->
<?php require_once("../includes/db_connection.php"); ?>
<table class="table table-hover" id='salestableid'>
<thead>
<tr class= "default" style="background-color: #e18728">
<th><font color = "white">Action</font></th>
<th width="200"><font color = "white">Product</th>
<th><font color = "white">Quantity</th>
<th width="75"><font color = "white">Price</th>
<th width ="90"><font color = "white">Total</th>
</tr>
</thead>
<tbody>
<tr>
<?php
$user_query = mysqli_query($connection, "SELECT saleslog.itemid, saleslog.qty, saleslog.date, saleslog.total, saleslog.id, items.`name`, items.description, items.retailprice FROM saleslog LEFT JOIN items ON items.id = saleslog.itemid")or die(mysqli_error());
while($row = mysqli_fetch_array($user_query)){
$id = $row['id'];
?>
<tr>
<td><a href="delete_salesitem.php?id=<?php echo urlencode($row['id']); ?>" class="btn btn-danger glyphicon glyphicon-trash btn-xs"></a></td>
<td><?php echo $row['name']; ?></td>
<td>      <?php echo $row['qty']; ?></td>
<td> <?php echo number_format($row['retailprice'],2); ?></td>
<?php
$total = $row['qty'] * $row['retailprice'];
?>
<td><?php echo number_format($total,2); ?></td>
</tr>
<?php } ?>
</tr>
</tbody>
</table>
<!-- End of Page SALESTABLE.PHP -->
<!--SALES_COUNT.PHP -->
<?php require_once("../includes/db_connection.php"); ?>
<?php
$count_client= mysqli_query($connection, "SELECT * FROM saleslog");
$count = mysqli_num_rows($count_client);
?>
<?php
$totalsales= mysqli_query($connection, "SELECT SUM(total) AS totalpritems FROM saleslog");
while($totalperitems = mysqli_fetch_array($totalsales)){
$total_sales = $totalperitems['totalpritems'];
}
?>
<table class='table' style="border-style: dotted" id="sales_countid">
<tr class='' style="border-style: dotted">
<td width="50" >Total Items: </td>
<td width="50"align="right"><?php echo $count; ?></td>
<td width="50" >Total: </td>
<td width="50"align="right" >P <?php echo number_format($total_sales,2); ?></td>
</tr>
<tr class='' style="border-style: dotted">
<td width="50">Discount: </td>
<td width="50"align="right">0.00 </td>
<td width="50">Tax: </td>
<td width="50"align="right">0.00 </td>
</tr>
<tr style="border-style: dotted">
<td width>Total Payable: </td>
<td align="right">P <?php echo number_format($total_sales,2); ?></td>
<td></td>
<td></td>
</tr>
</table>
<!--End of Page SALES_COUNT.PHP -->
答案 0 :(得分：1)
在table1的刷新代码中，您需要刷新table。
table1.load(...)而不是下面代码中的table.load(...)。
var table1 = $("#sales_countid");
var refresh1 = function() {
table.load("sales_count.php", function() {
setTimeout(refresh1, 1);
});
};