我正试图从NSDate
获取UIDatePicker
,但它会不断地返回一个约会时间为20秒的日期时间。如何在swift中手动将NSDate
的秒设置为零?
答案 0 :(得分:10)
extension Date {
var zeroSeconds: Date? {
get {
let calendar = Calendar.current
let dateComponents = calendar.dateComponents([.year, .month, .day, .hour, .minute], from: self)
return calendar.date(from: dateComponents)
}
}
}
用法:
let date1 = Date().zeroSeconds
let date2 = Date()
print(date2.zeroSeconds)
答案 1 :(得分:6)
来自Swift的answer:
var date = NSDate();
let timeInterval = floor(date .timeIntervalSinceReferenceDate() / 60.0) * 60.0
date = NSDate(timeIntervalSinceReferenceDate: timeInterval)
答案 2 :(得分:5)
这是在 Swift 3 中执行此操作的方法。
在此示例中,我删除了日期组件中的秒数:
let date = picker.date
let calendar = Calendar.current
let components = calendar.dateComponents([.year, .month, .day, .hour, .minute], from: date)
let fullMinuteDate = calendar.date(from: components)!
答案 3 :(得分:4)
可以使用
将日期截断为整分钟let date = NSDate()
let cal = NSCalendar.currentCalendar()
var fullMinute : NSDate?
cal.rangeOfUnit(.CalendarUnitMinute, startDate: &fullMinute, interval: nil, forDate: date)
println(fullMinute!)
在iOS 8上,这可以更简单地完成
let fullMinute = cal.nextDateAfterDate(date, matchingUnit: .CalendarUnitSecond,
value: 0,
options: .MatchNextTime | .SearchBackwards)!
println(fullMinute)
这两种方法都可以很容易地适应截断到整整一小时,一天,一个月......
答案 4 :(得分:2)
重新格式化日期:
func stripSecondsFromDate(date: NSDate) -> NSDate {
let dateFormatter = NSDateFormatter()
dateFormatter.dateFormat = "yyyy-MM-dd HH:mm"
let str = dateFormatter.stringFromDate(date)
let newDate = dateFormatter.dateFromString(str)!
return newDate
}
答案 5 :(得分:0)
let date = calendar.date(bySettingHour: 0,
minute: 0,
second: 0,
of: now,
matchingPolicy: .strict,
repeatedTimePolicy: .first,
direction: .backward)
还有另一种方法,还有两个参数:matchingpolicy和repeatedTimePolicy。
let formatter = ISO8601DateFormatter()
formatter.timeZone = TimeZone.current // defaults to GMT
let string = formatter.string(from: date!)
print(string) // 2019-03-27T00:00:00+01:00
要检查结果:
{{1}}
答案 6 :(得分:0)
我知道这不能直接解决NSDate
,但是还是值得的-我在Date
上也遇到了同样的问题,也因为我认为这可能成为更干净的方法。
extension Calendar {
/// Removes seconds `Calendar.Component` from a `Date`. If `removingFractional` is `true`, it also
/// removes all fractional seconds from this particular `Date`.
///
/// `removingFractional` defaults to `true`.
func removingSeconds(fromDate date: Date, removingFractional removesFractional: Bool = true) -> Date? {
let seconds = component(.second, from: date)
let noSecondsDate = self.date(byAdding: .second, value: -seconds, to: date)
if removesFractional, let noSecondsDate = noSecondsDate {
let nanoseconds = component(.nanosecond, from: noSecondsDate)
return self.date(byAdding: .nanosecond, value: -nanoseconds, to: noSecondsDate)
}
return noSecondsDate
}
}
现在,为了解决您的问题,我们创建了函数removingSeconds(fromDate: removingFractional)
。这非常简单-如您在函数文档中所见。它删除了.second
组件,如果removingFractional
是true
,它也删除了该Date
可能具有的小数秒-或.nanosecond
组件。 / p>