在swift中设置NSDate 0秒

时间:2015-04-22 06:14:46

标签: ios swift nsdate nsdatepicker

我正试图从NSDate获取UIDatePicker,但它会不断地返回一个约会时间为20秒的日期时间。如何在swift中手动将NSDate的秒设置为零?

7 个答案:

答案 0 :(得分:10)

extension Date {

    var zeroSeconds: Date? {
        get {
            let calendar = Calendar.current
            let dateComponents = calendar.dateComponents([.year, .month, .day, .hour, .minute], from: self)
            return calendar.date(from: dateComponents)
        }
    }

}

用法:

let date1 = Date().zeroSeconds

let date2 = Date()
print(date2.zeroSeconds)

答案 1 :(得分:6)

来自Swift的answer

var date = NSDate();
let timeInterval = floor(date .timeIntervalSinceReferenceDate() / 60.0) * 60.0
date = NSDate(timeIntervalSinceReferenceDate: timeInterval)

答案 2 :(得分:5)

这是在 Swift 3 中执行此操作的方法。

在此示例中,我删除了日期组件中的秒数:

let date = picker.date
let calendar = Calendar.current
let components = calendar.dateComponents([.year, .month, .day, .hour, .minute], from: date)
let fullMinuteDate = calendar.date(from: components)!

在操场上工作: Removing the seconds component from a date

答案 3 :(得分:4)

可以使用

将日期截断为整分钟
let date = NSDate()

let cal = NSCalendar.currentCalendar()
var fullMinute : NSDate?
cal.rangeOfUnit(.CalendarUnitMinute, startDate: &fullMinute, interval: nil, forDate: date)
println(fullMinute!)

在iOS 8上,这可以更简单地完成

let fullMinute = cal.nextDateAfterDate(date, matchingUnit: .CalendarUnitSecond,
                      value: 0,
                      options: .MatchNextTime | .SearchBackwards)!
println(fullMinute)

这两种方法都可以很容易地适应截断到整整一小时,一天,一个月......

答案 4 :(得分:2)

重新格式化日期:

func stripSecondsFromDate(date: NSDate) -> NSDate {
  let dateFormatter = NSDateFormatter()
  dateFormatter.dateFormat = "yyyy-MM-dd HH:mm"
  let str = dateFormatter.stringFromDate(date)
  let newDate = dateFormatter.dateFromString(str)!

  return newDate
}

答案 5 :(得分:0)

let date = calendar.date(bySettingHour: 0,
                         minute: 0,
                         second: 0,
                         of: now,
                         matchingPolicy: .strict,
                         repeatedTimePolicy: .first,
                         direction: .backward)

还有另一种方法,还有两个参数:matchingpolicyrepeatedTimePolicy

let formatter = ISO8601DateFormatter()
formatter.timeZone = TimeZone.current // defaults to GMT
let string = formatter.string(from: date!)
print(string) // 2019-03-27T00:00:00+01:00

要检查结果:

{{1}}

答案 6 :(得分:0)

我知道这不能直接解决NSDate,但是还是值得的-我在Date上也遇到了同样的问题,也因为我认为这可能成为更干净的方法。

extension Calendar {
    /// Removes seconds `Calendar.Component` from a `Date`. If `removingFractional` is `true`, it also
    /// removes all fractional seconds from this particular `Date`.
    ///
    /// `removingFractional` defaults to `true`.
    func removingSeconds(fromDate date: Date, removingFractional removesFractional: Bool = true) -> Date? {
        let seconds = component(.second, from: date)
        let noSecondsDate = self.date(byAdding: .second, value: -seconds, to: date)

        if removesFractional, let noSecondsDate = noSecondsDate {
            let nanoseconds = component(.nanosecond, from: noSecondsDate)
            return self.date(byAdding: .nanosecond, value: -nanoseconds, to: noSecondsDate)
        }

        return noSecondsDate
    }
}

现在,为了解决您的问题,我们创建了函数removingSeconds(fromDate: removingFractional)。这非常简单-如您在函数文档中所见。它删除了.second组件,如果removingFractionaltrue,它也删除了该Date可能具有的小数秒-或.nanosecond组件。 / p>