Question

我正在尝试从列表中删除子列表并收到此错误： ValueError：list.remove（x）：x不在列表中

我希望删除子列表，尽管x只有少数来自子字符串

类似的东西：

list_a=[[1,2,3],[4,5,6]]

list_a.remove([1,3])

list_a

[4,5,6]

来自以下评论：

我有产品清单：

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

lst[0]，lst[2]和lst[3]对于每种产品都是唯一的。我希望通过这三个元素来删除整个子列表：

>>> products.remove(['0001', 'Food', 'ISR'])
>>> products
['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']

def del_product(depot, product_data):
'''
    del_product
    delets a validated product data from the depot
    if such a product does not exist in the depot
    then no action is taken

    arguments:
    depot - list of lists
    product_data - list

    return value: boolean
'''

# Your code goes her

if validate_product_data(product_data)==True:
    for product in depot:
        if equal_products(product, product_data)==True:
            rem = set(product_data)
            for x in reversed(depot):
                if rem.issubset(x):
                    depot.remove(x)

            return True
        else:
            continue
    return False

Answer 1

您可以检查[1,3]是否为set.issubset的子集：

list_a = [[1,2,3],[4,5,6]]

rem = set([1,3])

list_a[:] = [ x for x in list_a if not rem.issubset(x)]
print(list_a)

s.issubset（t）s＆lt; = t测试s中的每个元素是否都在t

使用list_a[:]更改原始列表。

使用您的产品列表完全相同：

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

rem = set(['0001', 'Food', 'ISR'])

products[:] = [ x for x in products if not rem.issubset(x)]
print(products)
[['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

使用循环，如果它更容易遵循，你可以组合反转和issubset：

products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

rem = set(['0001', 'Food', 'ISR'])   

for x in reversed(products):
    if rem.issubset(x):
        products.remove(x)
print(products)

Answer 2

>>> list_a = [[1,2,3],[4,5,6]]
>>> bad = [1,3]
>>> list_a = [l for l in list_a if all(e not in l for e in bad)]
>>> list_a
[[4, 5, 6]]

现在实际问题已经揭晓：

>>> products=[['0001', 'Hummus', 'Food', 'ISR', '10-04-2015'], ['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]
>>> to_remove=['0001', 'Food', 'ISR']
>>> products = [l for l in products if [l[0], l[2], l[3]] != to_remove]
>>> products
[['0002', 'Guinness', 'Food', 'IRL', '11-04-2015']]

使用包含Product，Food，code，{{1的name或category对象，转移到OO方法可能会更好}}和label属性。

Answer 3

list_a = [sub for sub in list_a if not all(i in [1, 3] for i in sub)]

如果我只有少数子列表元素，如何从列表中删除整个子列表？蟒蛇

3 个答案: