构造函数参数值未实现

时间:2015-04-19 21:53:36

标签: java constructor

我正在创建一个非常简单的编码器,它将对字符串中的字符进行随机播放。我把它写成将这个字符串分成两半,形成两个新的变量。用户选择他们想要的shuffle数量,并将其作为新类构造函数中的参数传递 - 然后应该在整个类中使用该shuffle值。我的不是。 shuffleEncryption方法使用类变量0。我知道这一定是非常明显的事情,但我并没有抓住它。 :/

//来自主类

        System.out.println("Enter message to encrypt: ");
        String message = input.next();
        System.out.print("Number of shuffles: " );
        int numShuffles = input.nextInt();
        ShuffleCipher shuffle = new ShuffleCipher(numShuffles);
        System.out.println(shuffle.encode(message));

// shuffle类

public class ShuffleCipher implements MessageEncoder {
int shuffle;

public ShuffleCipher(int shuffle) {
    shuffle = this.shuffle;     
}

private String shuffleEncryption(String str) {
   int middle = str.length()/2;
   int loop = 1;
   System.out.println("shift" + shuffle);
   StringBuilder sb = new StringBuilder();

   do {
        String firstHalf = str.substring(0, middle);
        System.out.println("first:" + firstHalf);
        String secondHalf = str.substring(middle);
        System.out.println("second:" + secondHalf);

        for(int i = 0, j = 0; i < firstHalf.length(); i++, j++) {
            sb = sb.append(secondHalf.charAt(i));

           if(j < secondHalf.length()) {
           sb = sb.append(firstHalf.charAt(i));           
       }
       str = sb.toString();
   }
   loop++;
   } while (loop <= shuffle);

    return str;
 } 

@Override
public String encode(String plainText) {
    String shuffled; 
    shuffled = shuffleEncryption(plainText);
    return shuffled;
 }
}

1 个答案:

答案 0 :(得分:1)

您没有在构造函数中设置shuffle成员变量。

更改: -

public ShuffleCipher(int shuffle) {
    shuffle = this.shuffle;     
}

到此: -

public ShuffleCipher(int shuffle) {
    this.shuffle = shuffle;     
}