有界函数在Python中显示地址

Question

class NonVerticalLine:

    def __init__(self, point_1, point_2):

            self.point_1=point_1
            self.point_2=point_2


    def slope(self):

            p1=self.point_1
            p2=self.point_2
            return (p2.y-p1.y)/(p2.x-p1.x)

当我将值传递给_init并访问函数斜率时，它给出了---＆gt;

>>> from quiz_5 import *

>>> p1 = Point(1,2)

>>> p2 = Point(4,4)

>>> line = NonVerticalLine(point_1 = p1, point_2 = p2)

>>> line.slope
<bound method NonVerticalLine.slope of <quiz_5.NonVerticalLine object at 0x105b00160>>

应为0.6666666666666666

Answer 1

在这种情况下，请尝试

class NonVerticalLine:

    def __init__(self, point_1, point_2):

            self.point_1=point_1
            self.point_2=point_2

    @property
    def slope(self):

            p1=self.point_1
            p2=self.point_2
            return (p2.y-p1.y)/(p2.x-p1.x)

@property装饰器用于在Python中实现getter和setter，因此line.slope等同于没有装饰器的line.slope()。在这种情况下，似乎这种行为就是你想要的。