我想将SQLite database中的许多数据库行发送到webserver内的PostgreSQL数据库。我知道如何将send传统的键值对数据发送到webserver，但在我的情况下，我想从{{1}发送很多 records数据库。以下是我的传统SQLite代码：
post获取private void postData(String p_url) {
String donnees = ""; // here are the data to post
try {
donnees = URLEncoder.encode("identifiant1", "UTF-8")+ "="+URLEncoder.encode("valeur1", "UTF-8");
donnees += "&"+URLEncoder.encode("identifiant2", "UTF-8")+ "=" + URLEncoder.encode("valeur2", "UTF-8"); // traditional key-value pair for posting data
HttpURLConnection urlConnection = null;
OutputStreamWriter writer = null;
try {
URL url = new URL(p_url);
try {
urlConnection = (HttpURLConnection)url.openConnection();
urlConnection.setDoOutput(true);
urlConnection.setChunkedStreamingMode(0);
writer = new OutputStreamWriter(urlConnection.getOutputStream());
writer.write(donnees);
writer.flush();
} catch (IOException e) {
error = true;
err = contextInsideDialogue.getResources().getString(R.string.errAccessError);
} finally {
if (writer != null) { try { writer.close(); } catch (IOException e) {} }
if (urlConnection != null) { urlConnection.disconnect(); }
}
} catch (MalformedURLException e) {
error = true;
err = contextInsideDialogue.getResources().getString(R.string.errBadUrl);
}
} catch (UnsupportedEncodingException e1) {
error = true;
err = contextInsideDialogue.getResources().getString(R.string.errEncodageUTF8);
}
}
条记录的方法：
SQLite网络服务器端的PHP脚本：
public ArrayList<Parcelle> getAllNewOrModifiedParcelles() {
ArrayList<Parcelle> parcelles = new ArrayList<Parcelle>();
String selectQuery = "SELECT * FROM " + T_PARCELLE + " WHERE bien_code != '0' AND ( updated = 'true' OR new_enreg = 'true')";
Cursor c = bd.rawQuery(selectQuery, null);
if (c != null && c.moveToFirst()) {
do {
Parcelle p = new Parcelle();
p.setBien_code(c.getString(0));
p.setDecoup_terri_code(c.getString(1));
p.setDec_decoup_terri_code(c.getString(2));
p.setBien_ident(c.getString(3));
p.setParcel_denomination(c.getString(4));
p.setParcel_porte_ppale(c.getString(5));
p.setParcel_porte_second(c.getString(6));
p.setParcel_superfi_totale(c.getString(7));
p.setParcel_superf_batie(c.getString(8));
p.setParcel_superf_non_batie(c.getString(9));
p.setParcel_superf_plani(c.getString(10));
p.setParcel_adresse(c.getString(11));
p.setParcel_date_deb_construct(c.getString(12));
p.setParcel_date_fin_construct(c.getString(13));
parcelles.add(p);
} while (c.moveToNext());
}
return parcelles;
}
那么在这种情况下如何构造要发送的数据呢？
答案 0 :(得分：0)
使用JSON似乎适合您的用例，以下是我的完成方式：
private void postJSON(String myurl) throws IOException {
java.util.Date date= new java.util.Date();
Timestamp timestamp = (new Timestamp(date.getTime()));
try {
JSONObject parameters = new JSONObject();
parameters.put("timestamp",timestamp);
parameters.put("jsonArray", new JSONArray(Arrays.asList(makeJSON())));
parameters.put("type", "Android");
parameters.put("mail", "xyz@gmail.com");
URL url = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
// conn.setReadTimeout(10000 /* milliseconds */);
// conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestProperty( "Content-Type", "application/json" );
conn.setDoOutput(true);
conn.setRequestMethod("POST");
OutputStream out = new BufferedOutputStream(conn.getOutputStream());
BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(out, "UTF-8"));
writer.write(parameters.toString());
writer.close();
out.close();
int responseCode = conn.getResponseCode();
// System.out.println("\nSending 'POST' request to URL : " + url);
// System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
// System.out.println(response.toString());
}catch (Exception exception) {
System.out.println("Exception: "+exception);
}
}
这是我的makeJSON方法，类似于从SQLite读取然后转换为JSON的用例：
public JSONArray makeJSON(){
mCur = dbHelper.makeJSONBackup();
if(mCur != null && mCur.moveToFirst()){
do{
try{
//NotificationDateFor, TypeNotification, DOB, FriendsName, imageUri, RadioType FROM Notifications
JSONObject jObj = new JSONObject();
String notificationDateFor = mCur.getString(mCur.getColumnIndexOrThrow("NotificationDateFor"));
String typeNotification = mCur.getString(mCur.getColumnIndexOrThrow("TypeNotification"));
String dob = mCur.getString(mCur.getColumnIndexOrThrow("DOB"));
String friendsName = mCur.getString(mCur.getColumnIndexOrThrow("FriendsName"));
String imageUri = mCur.getString(mCur.getColumnIndexOrThrow("imageUri"));
if(imageUri.contains("/data/data/com.exa")){
}
String radioType = mCur.getString(mCur.getColumnIndexOrThrow("RadioType"));
jObj.put("NotificationDateFor", notificationDateFor);
jObj.put("DOB", dob);
jObj.put("TypeNotification", typeNotification);
jObj.put("FriendsName", friendsName);
jObj.put("imageUri", imageUri);
jObj.put("RadioType", radioType);
jArr.put(jObj);
}catch(Exception e){
System.out.println("Exception: "+e);
}
}while(mCur.moveToNext());
}
return jArr;
}
答案 1 :(得分：0)
我用过：
values[]=stringarrayitem1&values[]=stringarrayitem2&values[]=stringarrayitem3
作为url参数