Question

我正在构建一个PHP日历，它连接到包含日期列表的数据库。我已设法构建日历，连接到数据库，并显示日期。但是，我没有简单地更改数据库中找到日期的类，而是获得重复的日期。

我的PHP代码：

<?php
/* program name: Build Calender */
/* description: build calender */
/* 1 -> build table */
/* 2 -> add headings */
/* 3 -> add blanks */
/* 4 -> connect to db */
/* 5 -> check if dates in db = dates in calendar */
/* 6 ->  td with diff id */
/* 7 -> add remaining blanks */

$month = (int) (isset($_GET['month']) ? $_GET['month'] : date('m'));
$year =  (int) (isset($_GET['year']) ? $_GET['year'] : date('Y'));

echo "<h1 style='float:left; padding-right:30px;'>".date("F",mktime(0,0,0,$month,1,$year))." ".$year."</h1>";

$next = '<a href="?month='.($month != 12 ? $month + 1 : 1).'&year='.($month != 12 ? $year : $year + 1).'" class="control">Next</a>';

/* "previous month" control */
$previous = '<a href="?month='.($month != 1 ? $month - 1 : 12).'&year='.($month != 1 ? $year : $year - 1).'" class="control">Previous </a>';

$controls = $previous."|".$next;
echo $controls;

$headings = array(0 =>'mon','tue','wed','thurs','fri','sat','sun');
$running_day = date('w',mktime(0,0,0,$month,0,$year));
$days_in_month = date('t',mktime(0,0,0,$month,1,$year));
$days_in_this_week = 1;
$day_counter = 1;
$dates_array = array();
$gourmet_type = "";

echo"<table border='1px'>\n";
for ($weeks = 0; $weeks<= 5 ; $weeks++)
{
    echo "<tr>\n";
    for ($days = 0; $days <= 6 ; $days++)
    {
        if($weeks == 0)
        {
            echo"<td>".$headings[$days]."</td>\n";  
        }
        else if ($weeks == 1 && $days < $running_day)  //Generates first row
        {
            echo "<td class='day-cell'>"."yy"."</td>\n";
        }
        else if ($day_counter <= $days_in_month)  //Adds the rest of the days
        {
        // varialbes for day-cell //
            $available  = "<td class='day-cell available' id='$day_counter'>".$day_counter."</td>\n";
            $lunch = "<td class='day-cell lunch' id='$day_counter'>".$day_counter."</td>\n";
            $dinner = "<td class='day-cell dinner' id='$day_counter'>".$day_counter."</td>\n";
            $fullday = "<td class='day-cell fullday' id='$day_counter'>".$day_counter."</td>\n";
            echo $available;
            $datestring = $day_counter.".".$month.".".$year;
            /** QUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !!  IF MATCHES FOUND, PRINT THEM !! **/
            $db_link = mysql_connect("$host", "$user", "$password") or die('Cannot connect');
            mysql_select_db("$database",$db_link) or die('Cannot select the DB');
            $query = "SELECT * FROM reservations";
            $result = mysql_query($query,$db_link) or die('cannot get results!');
            while($row = mysql_fetch_assoc($result))
            {
            if  ($row['date_of_reservation'] == $datestring && $row['reservationType'] == "LUNCH")
                { 
                    echo $lunch;                     
                }
                else if ($row['date_of_reservation'] ==  $datestring &&  $row['reservationType'] == "DINNER")
                {
                    echo $dinner;
                }
                else if ($row['date_of_reservation'] == $datestring && $row['reservationType'] == "FULLDAY")
                {
                    echo $fullday;
                }
            }
            $day_counter++;
            }
        else  //Adds the blanks at the end
        {
            echo "<td class='day-cell'>"."yy"."</td>\n";
        }
    }
    echo "</tr>\n"; 
}
echo "</table>";

＆GT;

这是我在浏览器中得到的结果：

<h1 style='float:left; padding-right:30px;'>April 2015</h1><a href="?month=3&year=2015" class="control">Previous </a>|<a href="?month=5&year=2015" class="control">Next</a>
<table border='1px'>
<tr>
   <td>mon</td>
   <td>tue</td>
   <td>wed</td>
   <td>thurs</td>
   <td>fri</td>
   <td>sat</td>
   <td>sun</td>
</tr>
<tr>
   <td class='day-cell'>yy</td>
   <td class='day-cell'>yy</td>
   <td class='day-cell available' id='1'>1</td> <!--should hide -->
   <td class='day-cell dinner' id='1'>1</td>
   <td class='day-cell available' id='2'>2</td>
   <td class='day-cell available' id='3'>3</td>
   <td class='day-cell available' id='4'>4</td>
   <td class='day-cell available' id='5'>5</td> <!--should hide -->
   <td class='day-cell lunch' id='5'>5</td>  
</tr>
<tr>
    <td class='day-cell available' id='6'>6</td>
    <td class='day-cell available' id='7'>7</td>
    <td class='day-cell available' id='8'>8</td>
    <td class='day-cell available' id='9'>9</td>
    <td class='day-cell fullday' id='9'>9</td>
    <td class='day-cell available' id='10'>10</td>
    <td class='day-cell available' id='11'>11</td>
    <td class='day-cell available' id='12'>12</td>
</tr>
<tr>
     <td class='day-cell available' id='13'>13</td>
     <td class='day-cell available' id='14'>14</td>
     <td class='day-cell available' id='15'>15</td>
     <td class='day-cell available' id='16'>16</td>
     <td class='day-cell available' id='17'>17</td> <!--should hide -->
     <td class='day-cell lunch' id='17'>17</td>
     <td class='day-cell available' id='18'>18</td> <!--should hide -->
     <td class='day-cell dinner' id='18'>18</td>
     <td class='day-cell available' id='19'>19</td> <!--should hide -->
     <td class='day-cell lunch' id='19'>19</td>
 </tr>
 <tr>
      <td class='day-cell available' id='20'>20</td>
      <td class='day-cell available' id='21'>21</td> <!--should hide -->
      <td class='day-cell lunch' id='21'>21</td>
      <td class='day-cell available' id='22'>22</td>
      <td class='day-cell available' id='23'>23</td>
      <td class='day-cell available' id='24'>24</td>
      <td class='day-cell available' id='25'>25</td>
      <td class='day-cell available' id='26'>26</td>
 </tr>
 <tr>
      <td class='day-cell available' id='27'>27</td>
      <td class='day-cell available' id='28'>28</td>
      <td class='day-cell available' id='29'>29</td>
      <td class='day-cell available' id='30'>30</td> <!--should hide -->
      <td class='day-cell lunch' id='30'>30</td>
      <td class='day-cell'>yy</td>
      <td class='day-cell'>yy</td>
      <td class='day-cell'>yy</td>
 </tr>
 </table>

Answer 1

我认为你需要处理$ available和$ lunch，$ dinner，$ fullday。我试图改变。请检查

<?php
    /* program name: Build Calender */
    /* description: build calender */
    /* 1 -> build table */
    /* 2 -> add headings */
    /* 3 -> add blanks */
    /* 4 -> connect to db */
    /* 5 -> check if dates in db = dates in calendar */
    /* 6 ->  td with diff id */
    /* 7 -> add remaining blanks */

    $month = (int) (isset($_GET['month']) ? $_GET['month'] : date('m'));
    $year =  (int) (isset($_GET['year']) ? $_GET['year'] : date('Y'));

    echo "<h1 style='float:left; padding-right:30px;'>".date("F",mktime(0,0,0,$month,1,$year))." ".$year."</h1>";

    $next = '<a href="?month='.($month != 12 ? $month + 1 : 1).'&year='.($month != 12 ? $year : $year + 1).'" class="control">Next</a>';

    /* "previous month" control */
    $previous = '<a href="?month='.($month != 1 ? $month - 1 : 12).'&year='.($month != 1 ? $year : $year - 1).'" class="control">Previous </a>';

    $controls = $previous."|".$next;
    echo $controls;

    $headings = array(0 =>'mon','tue','wed','thurs','fri','sat','sun');
    $running_day = date('w',mktime(0,0,0,$month,0,$year));
    $days_in_month = date('t',mktime(0,0,0,$month,1,$year));
    $days_in_this_week = 1;
    $day_counter = 1;
    $dates_array = array();
    $gourmet_type = "";

    echo"<table border='1px'>\n";
    for ($weeks = 0; $weeks<= 5 ; $weeks++)
    {
        echo "<tr>\n";
        for ($days = 0; $days <= 6 ; $days++)
        {
            if($weeks == 0)
            {
                echo"<td>".$headings[$days]."</td>\n";  
            }
            else if ($weeks == 1 && $days < $running_day)  //Generates first row
            {
                echo "<td class='day-cell'>"."yy"."</td>\n";
            }
            else if ($day_counter <= $days_in_month)  //Adds the rest of the days
            {
            // varialbes for day-cell //
                $available  = "<td class='day-cell available' id='$day_counter'>".$day_counter."</td>\n";
                $lunch = "<td class='day-cell lunch' id='$day_counter'>".$day_counter."</td>\n";
                $dinner = "<td class='day-cell dinner' id='$day_counter'>".$day_counter."</td>\n";
                $fullday = "<td class='day-cell fullday' id='$day_counter'>".$day_counter."</td>\n";
                //echo $available;
                $toshow="";
                $datestring = $day_counter.".".$month.".".$year;
                /** QUERY THE DATABASE FOR AN ENTRY FOR THIS DAY !!  IF MATCHES FOUND, PRINT THEM !! **/
                $db_link = mysql_connect("$host", "$user", "$password") or die('Cannot connect');
                mysql_select_db("$database",$db_link) or die('Cannot select the DB');
                $query = "SELECT * FROM reservations";
                $result = mysql_query($query,$db_link) or die('cannot get results!');
                while($row = mysql_fetch_assoc($result))
                {
                if  ($row['date_of_reservation'] == $datestring && $row['reservationType'] == "LUNCH")
                    { 
                       $toshow=$lunch;                     
                    }
                    else if ($row['date_of_reservation'] ==  $datestring &&  $row['reservationType'] == "DINNER")
                    {
                        $toshow=$dinner;
                    }
                    else if ($row['date_of_reservation'] == $datestring && $row['reservationType'] == "FULLDAY")
                    {
                       $toshow=$fullday;
                    }

                }

                if($toshow==""){
                echo $available;
                }
                else{
                echo $toshow;
                }

                $day_counter++;
                }
            else  //Adds the blanks at the end
            {
                echo "<td class='day-cell'>"."yy"."</td>\n";
            }
        }
        echo "</tr>\n"; 
    }
    echo "</table>";

Answer 2

我不是很擅长php.But我认为你的代码在

$fullday = "<td class='day-cell fullday' id='$day_counter'>".$day_counter."</td>\n";
echo $available;

此回音将输出您的所有class='day-cell available' dt。

所以我认为这个回声应该移到while($row = mysql_fetch_assoc($result))循环中的最后一个。

看起来像

else if ($row['date_of_reservation'] == $datestring && $row['reservationType'] == "FULLDAY")
            {
                echo $fullday;
            }
else 
     {
                echo $available;
     }

在php日历中显示事件

2 个答案: