Question

R今天不喜欢我......

我有两个表通过cbind（）组合。标签1（ dwd_nogap ）是

  x1                 col1_x1       col2_x1      
A "1982 12 01 00:00" "        0.4" "          0"
B "1982 12 02 00:00" "       -0.5" "          0"
C "1982 12 03 00:00" "       -0.2" "          0"
D "1982 12 04 00:00" "         -1" "        0.1"
E "1982 12 05 00:00" "       -0.9" "          0"
F "1982 12 06 00:00" "        3.7" "        4.1"

标签2（ dwd_gap ）是：

     x2                 col1_x2       col2_x2      
[1,] "1982 12 01 00:00" "        0.4" "          0"
[2,] "1982 12 03 00:00" "       -0.2" "          0"
[3,] "1982 12 04 00:00" "         -1" "        0.1"
[4,] "1982 12 05 00:00" "       -0.9" "          0"
[5,] "1982 12 06 00:00" "        3.7" "        4.1"
[6,] "1982 12 07 00:00" "          7" "        5.8"

我的合并命令是：

exporttab <- merge(x=dwd_nogap,y=dwd_gap,by.x=dwd_nogap[,1],by.y=dwd_gap[,1], fill=-9999)

在我看来，命令是正确的，但显然效果不好......

Error in fix.by(by.x, x) : 'by' must specify uniquely valid columns

Answer 1

而是给出要合并的列的名称：

exporttab <- merge(x=dwd_nogap, y=dwd_gap, by.x='x1', by.y='x2', fill=-9999)

Answer 2

这是我尝试的右外连接[根据我的要求]

m1 <- merge(x=companies,y=rounds2,by.x = companies$permalink,by.y = rounds2$company_permalink,all.y=TRUE)

fix.by（by.x，x）出错：'by'必须指定唯一有效的列

m1 <- merge(x=companies,y=rounds2,by.x = c("permalink"),by.y = c("company_permalink"),all.y = TRUE)

这很有用。

合并r会带来错误＆＃34;＆＃39;＆＃39;必须指定唯一有效的列＆＃34;

2 个答案: