我做了一个简单的测试,代码如下:
public class InterruptTest
{
public static class MyTask implements Runnable {
@Override
public void run() {
System.out.println("before sleep " + Thread.currentThread().isInterrupted());
System.out.println(Thread.currentThread());
Thread.currentThread().interrupt();
System.out.println("after sleep " + Thread.currentThread().isInterrupted());
}
}
public static void main(String[] str)
{
ExecutorService service = Executors.newFixedThreadPool(1);
// MyTask task1 = new MyTask();
Future<?> future1 = service.submit(new InterruptTest.MyTask());
Future<?> future2 = service.submit(new InterruptTest.MyTask());
try
{
Thread.sleep(10);
}
catch (InterruptedException e)
{
System.out.println("interrupted;");
}
}
}
输出是:
before sleep false
Thread[pool-1-thread-1,5,main]
after sleep true
**before sleep false** // line 4
Thread[pool-1-thread-1,5,main]
after sleep true
为什么第4行仍然输出错误?不对 ?因为当前池中只有一个线程,它应该在第一个任务中被中断,为什么它在第二个任务运行时仍然可用(不中断)?
提前致谢!
另一个问题是我修改了run函数,如下所示:
public static class MyTask implements Runnable {
@Override
public void run() {
System.out.println("before sleep " + Thread.currentThread().isInterrupted());
System.out.println(Thread.currentThread());
try
{
Thread.sleep(10);
}
catch (InterruptedException e)
{
System.out.println("interrupted;");
System.out.println("after sleep " + Thread.currentThread().isInterrupted());
System.out.println(Thread.currentThread());
}
}
}
一项任务的输出是:
before sleep false
Thread[pool-1-thread-1,5,main]
interrupted;
after sleep false
任务应该通过thread.interrupt从睡眠中唤醒。但是当我使用Thread.currentThread()。isInterrupted()来检查它时,它仍然返回false。
将sleep()吃掉中断状态??
答案 0 :(得分:4)
查看ThreadPoolExecutor
的源代码,有一个名为clearInterruptsForTaskRun
的私有方法记录为:
确保除非池正在停止,否则当前线程没有设置其中断