Question

昨天我开始使用一些新的colomns更新我的记分牌并在这里得到一些好的提示，所以我可以大胆地提出另一个问题吗？

简单的SQL在这里，但我需要将Case（）作为欧元汇总，以便显示在所有轮次中获得或损失的总欧元。

SELECT  t1.playerid, sum(t1.points) as totalpoints, count(t1.playerid) as rounds,avg(points) as avgpoints
   
           ,Case
            when count(t1.playerid) in(7,6)   and (select points from pokermax_scores as t4 where t1.playerid=t4.playerid and t1.tournamentid=t4.tournamentid) = 38 then 15
            when count(t1.playerid) in(7,6,5) and (select points from pokermax_scores as t4 where t1.playerid=t4.playerid and t1.tournamentid=t4.tournamentid) = 25 then 5
            when count(t1.playerid) in(5,4)   and (select points from pokermax_scores as t4 where t1.playerid=t4.playerid and t1.tournamentid=t4.tournamentid) = 38 then 10
            when count(t1.playerid) = 7       and (select points from pokermax_scores as t4 where t1.playerid=t4.playerid and t1.tournamentid=t4.tournamentid) = 16 then 0
            when count(t1.playerid) = 4       and (select points from pokermax_scores as t4 where t1.playerid=t4.playerid and t1.tournamentid=t4.tournamentid) = 25 then 0
            else -5       
            End as Euro

FROM pokermax_scores as t1
group by t1.playerid
order by avgpoints desc

返回： img“http://i62.tinypic.com/213iud0.png”

正如你所看到的那样，欧元并非总结，而只是随机的......

Answer 1

这是解决方案，首先创建一个子查询，收集所有信息raw，然后在主查询中汇总这个sum（）。

示例：

＆＃13;

select t3.playerid,sum(t3.Euro)
 from
 (
 
 select t2.playerid,t2.points,t2.tournamentid,
      Case
           when count(t1.playerid) in(7,6)   and t2.points = 38 then 15
           when count(t1.playerid) in(7,6,5) and t2.points = 25 then 5
           when count(t1.playerid) in(5,4)   and t2.points = 38 then 10
           when count(t1.playerid) = 7       and t2.points = 16 then 0
           when count(t1.playerid) = 4       and t2.points = 25 then 0
           else -5     
          End as Euro
 FROM pokermax_scores as t1, pokermax_scores as t2
 where t1.tournamentid = t2.tournamentid 
 group by t2.tournamentid, t2.playerid) as t3
 group by t3.playerid

＆＃13;

总和（计算每位玩家总欧元的情况

1 个答案: