Python导入文件，其元素为int to list

Question

我想读作int，是否有任何pythonic方法可以做到这一点？

f = open('p059_cipher.txt', 'rU')
holder = list((f.read().replace('"', '').split(',')))

Letters = list() 

for number in holder:
    Letters.append(int(number))

Answer 1

我试图从您的输入中猜测，但这可能会有效：

from ast import literal_eval

with open('p059_cipher.txt') as f:
    data = "[" + f.read() + "]"

result = list(map(int, literal_eval(data)))
# The call to list is only necessary if both
#   1. You explicitly need a LIST
#   2. You're running Python3
# If you're in Python2 or you just need to iterate, ignore the list call

这应该采取如下输入：

"1", "2", "3", "4", "12", "1003981890213"

并创建

result == [1, 2, 3, 4, 12, 1003981890213]

Answer 2

尝试以下方法：

with open('p059_cipher.txt', 'rU') as f:
    numbers = list(map(int, f.read().replace('"','').split(',')))

这会将包含1,2,"3"的文件转换为[1, 2, 3]（并将其另存为numbers）。