我有以下代码,它为我提供了30天的生产日期和产量。
select
(case when trunc(so.revised_due_date) <= trunc(sysdate)
then trunc(sysdate) else trunc(so.revised_due_date) end) due_date,
(case
when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD')
then 'CD' end) = 'CD'
and (case when so.tec_criteria in ('PI','MC')
then 'XX' else so.tec_criteria end) = 'OF'
then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD'
and so.plant = 'W'
and so.status_code between '4' and '8'
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)
我遇到的问题是没有计划生产的日期,日期不会出现在报告上。有没有办法填补丢失的日期。
即。目前的报告显示以下内容......
DUE_DATE CD_OF_VOLUME
14/04/2015 35,267.00
15/04/2015 71,744.00
16/04/2015 20,268.00
17/04/2015 35,156.00
18/04/2015 74,395.00
19/04/2015 3,636.00
21/04/2015 5,522.00
22/04/2015 15,502.00
04/05/2015 10,082.00
注意:缺少日期(2015年4月20日,2015年4月23日至2015年5月3日)
范围始终是sysdate的30天。 你如何填写缺少的日期? 你需要某种日历表吗?
由于
答案 0 :(得分:3)
您可以从SYSDATE
获取30天的时间段(我假设您要包含SYSDATE
?):
WITH mydates AS (
SELECT TRUNC(SYSDATE) - 1 + LEVEL AS due_date FROM dual
CONNECT BY LEVEL <= 31
)
然后使用上面的内容对您的查询执行LEFT JOIN
(将查询放入CTE也许不错):
WITH mydates AS (
SELECT TRUNC(SYSDATE) - 1 + LEVEL AS due_date FROM dual
CONNECT BY LEVEL <= 31
), myorders AS (
select
(case when trunc(so.revised_due_date) <= trunc(sysdate)
then trunc(sysdate) else trunc(so.revised_due_date) end) due_date,
(case
when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD')
then 'CD' end) = 'CD'
and (case when so.tec_criteria in ('PI','MC')
then 'XX' else so.tec_criteria end) = 'OF'
then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD'
and so.plant = 'W'
and so.status_code between '4' and '8'
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)
)
SELECT mydates.due_date, myorders.cd_of_volume
FROM mydates LEFT JOIN myorders
ON mydates.due_date = myorders.due_date;
如果您想在“缺失”日期而不是NULL
上显示零,请使用上面的COALESCE(myorders.cd_of_volume, 0) AS cd_of_volume
。
答案 1 :(得分:1)
你能做的是: 用你需要的所有日子创建一个新表。
WITH DAYS AS
(SELECT TRUNC(SYSDATE) - ROWNUM DDD
FROM ALL_OBJECTS
WHERE ROWNUM < 365)
SELECT
DAYS.DDD
FROM
DAYS;
然后在桌子之间进行全外连接:
select DUE_DATE , CD_OF_VOLUME , DDD
from (
select
(case when trunc(so.revised_due_date) <= trunc(sysdate)
then trunc(sysdate) else trunc(so.revised_due_date) end) due_date,
(case
when (case when sp.pr_typ in ('VV','VD') then 'DVD' when sp.pr_typ in ('RD','CD')
then 'CD' end) = 'CD'
and (case when so.tec_criteria in ('PI','MC')
then 'XX' else so.tec_criteria end) = 'OF'
then sum(so.revised_qty_due)
end) CD_OF_VOLUME
from shop_order so
left join scm_prodtyp sp
on so.prodtyp = sp.prodtyp
where so.order_type = 'MD'
and so.plant = 'W'
and so.status_code between '4' and '8'
and trunc(so.revised_due_date) <= trunc(sysdate)+30
group by trunc(so.revised_due_date), so.tec_criteria, sp.pr_typ
order by trunc(so.revised_due_date)
) full outer join NEW_TABLE new on ( new .DDD = DUE_DATE )
where new .DDD between /* */ AND /* */ /* pick your own limit) */
答案 2 :(得分:1)
您可以使用gaps
和connect by
来获取left join
:
假设您的架构是:
create table tbl(DUE_DATE date, CD_OF_VOLUME float);
insert into tbl values(to_date('14/04/2015','DD/MM/YYYY'),35267.00);
insert into tbl values(to_date('15/04/2015','DD/MM/YYYY'),71744.00);
insert into tbl values(to_date('16/04/2015','DD/MM/YYYY'),20268.00);
insert into tbl values(to_date('17/04/2015','DD/MM/YYYY'),35156.00);
insert into tbl values(to_date('18/04/2015','DD/MM/YYYY'),74395.00);
insert into tbl values(to_date('19/04/2015','DD/MM/YYYY'),3636.00);
insert into tbl values(to_date('21/04/2015','DD/MM/YYYY'),5522.00);
insert into tbl values(to_date('22/04/2015','DD/MM/YYYY'),15502.00);
insert into tbl values(to_date('04/05/2015','DD/MM/YYYY'),10082.00);
你可以说:
with cte as
(
select (select min(DUE_DATE)-1 from tbl)+ level as dt
from dual
connect by level <= (select max(DUE_DATE)-min(DUE_DATE) from tbl)
)
select to_char(c.dt,'DD/MM/YYYY') gap,null volume
from cte c
left join tbl t on c.dt=t.DUE_DATE
where t.DUE_DATE is null
order by c.dt
结果:
GAP VOLUME
20/04/2015 (null)
23/04/2015 (null)
24/04/2015 (null)
25/04/2015 (null)
26/04/2015 (null)
27/04/2015 (null)
28/04/2015 (null)
29/04/2015 (null)
30/04/2015 (null)
01/05/2015 (null)
02/05/2015 (null)
03/05/2015 (null)
注意:您可以在原始查询中实现此功能,最简单的方法是将查询包装起来,并将其用作子查询,而不是上面代码段中的 tbl 。