Question

我有两种型号：House＆amp;室

我有一个自定义表格，如下所示：

class HouseFormCustom(forms.ModelForm):

    rooms_number = forms.CharField()

    def save(self, commit=True):
        rooms_number = self.cleaned_data.get('rooms_number', None)
        return super(HouseFormCustom, self).save(commit=commit)

    class Meta:
        model = House


class HouseAdmin(admin.ModelAdmin):
    form = HouseFormCustom


admin.site.register(House, HouseAdmin)

我想使用rooms_number来保存基于DB X房间的模型并连接到最后创建的房屋。

像：

for x in range(0, rooms_number):
  r = Room()
  r.house = last_id_house
  r.save()

任何提示？我的意思是，我应该把最后一段代码放在哪里？

Answer 1

解决了这个问题：

class HouseFormCustom(forms.ModelForm):

    rooms_number = forms.IntegerField(required=False)

    class Meta:
        model = House


class HouseAdmin(admin.ModelAdmin):

    form = HouseFormCustom

    def save_model(self, request, obj, form, change):
        obj.save()

        rooms_number = request.POST.get('rooms_number', None)

        if(rooms_number):
            Room.objects.bulk_create([Room(house=obj) for x in range(0, rooms_number)])


admin.site.register(House, HouseAdmin)

使用django admin save上的最后一个id创建其他模型

1 个答案: