我试图显示用户创建表单的单个列,我有一个表和用户会话设置。我需要它,以便只为创建它的用户显示该列。
这是表格
<form action="core/process.php" method="post" id="registration" >
<input type="hidden" name="formID" value="Product_Tracker" />
<input type="hidden" name="id_user" value="<?php echo $_SESSION['name_of_user']; ?>" />
<p>Name of product:<input type="text" name="Name of Product" class="input" />
<p>Please select the tests that were done on the product.</p>
<p>In Circuit Test (ICT): Yes: <input type="radio" name="ICT" value="yes" /> No: <input type="radio" name="ICT" value="no" /></p>
<p>Visual Inspection: Yes: <input type="radio" name="Visual Inspection" value="yes" /> No: <input type="radio" name="Visual Inspection" value="no" /></p>
<p>XRAY: Yes: <input type="radio" name="XRAY" value="yes" /> No: <input type="radio" name="XRAY" value="no" /></p>
<p>Automated Optical Inspection (AOI): Yes: <input type="radio" name="AOI" value="yes" /> No: <input type="radio" name="AOI" value="no" /></p>
<!--<p>Checkbox1 <input type="checkbox" name="checkbox" value="checkbox1" /> Checkbox2: <input type="checkbox" name="checkbox" value="checkbox2" /></p>-->
<input type="submit" value="Submit" />
<p>
<a href='access-controlled.php'>Back</a>
</p>
</form>
</div>
</body>
</html>
<?php VDEnd(); ?>
我试过这个,但它不起作用,
$con = mysql_connect("","","");
if (!$con){
die("Can not connect: " . mysql_error());
}
mysql_select_db("database",$con);
$result = mysql_query("SELECT id_user, Name_of_product FROM Product_Tracker WHERE id_user=$_SESSION['name_of_user']");
while ($row = mysql_fetch_assoc($result)) {
echo $row['Name_of_Product'];
echo "<br />";
这样做了;
mysql_select_db("database",$con);
$id=$_SESSION['name_of_user'];
$result = mysql_query("SELECT id_user, Name_of_product FROM Product_Tracker WHERE id_user='$id'");
while ($row = mysql_fetch_array($result))
{
echo $row['Name_of_product'] . "<br/>";
}
mysql_query($query);
mysql_close($con);
&GT;
答案 0 :(得分:2)
$id=$_SESSION['name_of_user'];
$result = mysql_query("SELECT id_user, Name_of_product FROM Product_Tracker WHERE id_user='$id'");