Question

所以我正在尝试制作圆形计算器。一个人需要添加半径，直径，S或P，程序应该给出所有答案，但是当我添加一个东西时，程序会使用我添加到程序中的所有公式。我希望程序使用那些适合于那种情况的特定公式，例如，当我输入radius（r）时，程序将使用我为其添加的那些公式（//插入r时）而不是其他公式。我希望你们明白我的意思，抱歉我的英语不好，希望有人可以提供帮助。

public void onButtonClick(View v) {
    EditText a1 = (EditText) findViewById(R.id.TFnum1);
    EditText a2 = (EditText) findViewById(R.id.TFnum2);
    EditText a3 = (EditText) findViewById(R.id.TFnum6);
    EditText a4 = (EditText) findViewById(R.id.TFnum7);


    TextView tv = (TextView) findViewById(R.id.TFnum7); //P
    TextView tv1 = (TextView) findViewById(R.id.TFnum6); //S
    TextView tv2 = (TextView) findViewById(R.id.TFnum2); //d
    TextView tv3 = (TextView) findViewById(R.id.TFnum1); //r
    boolean flag = false;
    double num1, num2, num6, num7, ans;
    num1 = ParseDouble(a1.getText().toString());
    num2 = ParseDouble(a2.getText().toString());
    num6 = ParseDouble(a3.getText().toString());
    num7 = ParseDouble(a4.getText().toString());
    ans = 0;





    //when inserting r
    //d
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = 2 * num1;
    tv2.setText(ans + "");

    //S
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = 3.14 * (num1 * num1);
    tv1.setText(ans + "");

    //P
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = num1 * 3.14 * 2;
    tv.setText(ans + "");



    //when inserting d
    //r
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = num2 / 2;
    tv3.setText(ans + "");

    //S
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = (num2 / 2) * (num2 / 2) * 3.14;
    tv1.setText(ans + "");

    //P
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = (num2 / 2) * 3.14 * 2;
    tv.setText(ans + "");



   //when inserting S
   //r
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = Math.sqrt(num6 / 3.14);
    tv3.setText(ans + "");

    //d
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = Math.sqrt(num6 / 3.14) * 2;
    tv2.setText(ans + "");

    //P
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = (Math.sqrt(num6 / 3.14)) * 2 * 3.14;
    tv.setText(ans + "");



    //when inserting P
    //r
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = num7 / 6.28;
    tv3.setText(ans + "");

    //d
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = (num7 / 6.28) * 2;
    tv2.setText(ans + "");

    //S
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
    else ans = (num7 / 6.28) * (num7 /6.28) * 3.14;
    tv1.setText(ans + "");
}

private double ParseDouble(String number) {
    if (number!= null && number.length() > 0) {
        try {
            return Double.parseDouble(number);
        } catch(Exception e) {
            return -1;// Will return -1 in case of exception, you can change it with another value
        }
    }

    return 1;
}

Answer 1

问题是你拥有＆＃34; onClick（）＆＃34;中的所有方法。功能。所以它贯穿每一个。

我建议你这样做。

您可以创建4个方法，分别对应每个参数（R，S，D，P）。然后在你的onClick（）函数中，你将检查输入的位置，所以如果＆＃34; R＆＃34;输入后，您将调用相应的方法并发送相应的视图。

我希望下面的代码能更好地解释它：

全局声明以下内容（即在方法之外）：

boolean flag = false;
TextView tv;
TextView tv1;
TextView tv2;
TextView tv3;

public void onButtonClick(View v) {
    EditText a1 = (EditText) findViewById(R.id.TFnum1);
    EditText a2 = (EditText) findViewById(R.id.TFnum2);
    EditText a3 = (EditText) findViewById(R.id.TFnum6);
    EditText a4 = (EditText) findViewById(R.id.TFnum6);


    tv = (TextView) findViewById(R.id.TFnum7); //P
    tv1 = (TextView) findViewById(R.id.TFnum6); //S
    tv2 = (TextView) findViewById(R.id.TFnum2); //d
    tv3 = (TextView) findViewById(R.id.TFnum1); //r

    double num1, num2, num6, num7, ans;
    num1 = ParseDouble(a1.getText().toString());
    num2 = ParseDouble(a2.getText().toString());
    num6 = ParseDouble(a3.getText().toString());
    num7 = ParseDouble(a4.getText().toString());
    ans = 0;
    //this is where you will check whether values were entered
    //and also depending on which EditText is accepting the R value 
    //for argument sake 
    if(!a1.equals("")){
        onInsertR(v, num2, num1, ans);
    }

if(!a2.equals ("")){onInsertR(v, num2,num1,ans);}

if(!a3.equals ("")){onInsertR(v, num2,num1,ans);}

if(!a4.equals ("")){onInsertR(v, num2,num1,ans);}



}

public void onInsertR(View v, double num2, double num1, double ans){
    //when inserting r
    //d
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
        else ans = 2 * num1;
    tv2.setText(ans + "");

    //S
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = 3.14 * (num1 * num1);
    tv1.setText(ans + "");

    //P
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
        else ans = num1 * 3.14 * 2;
    tv.setText(ans + "");
}

public void onInsertD(View v, double num2,double ans){
    //when inserting d
    //r
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
        else ans = num2 / 2;
    tv3.setText(ans + "");

    //S
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = (num2 / 2) * (num2 / 2) * 3.14;
    tv1.setText(ans + "");

    //P
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = (num2 / 2) * 3.14 * 2;
    tv.setText(ans + "");
}

public void onInsertS(View v, double num2, double num6,double ans){
    //when inserting S
    //r
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
         else ans = Math.sqrt(num6 / 3.14);
    tv3.setText(ans + "");

    //d
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
        else ans = Math.sqrt(num6 / 3.14) * 2;
    tv2.setText(ans + "");

    //P
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = (Math.sqrt(num6 / 3.14)) * 2 * 3.14;
    tv.setText(ans + "");
}

public void onInsertP(View v, double num2, double num7,double ans){
    //when inserting P
    //r
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = num7 / 6.28;
    tv3.setText(ans + "");

    //d
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = (num7 / 6.28) * 2;
    tv2.setText(ans + "");

    //S
    if (v.getId() == R.id.Badd) if (num2 == 0) flag = true;
       else ans = (num7 / 6.28) * (num7 /6.28) * 3.14;
    tv1.setText(ans + "");
}

private double ParseDouble(String number) {
    if (number!= null && number.length() > 0) {
        try {
            return Double.parseDouble(number);
        } catch(Exception e) {
            return -1;// Will return -1 in case of exception, you can change     it with another value
        }
    }

return 1;
}

希望这可以帮助你。

让我知道它是怎么回事:)）

一切顺利！

无法制作圆计算器

1 个答案: