Question

我有一张桌子

name    score
samar   12
pradeep 30
garry   90

我想从上表中获得前2名。这可以通过row_number()函数完成。但它也适用于交叉申请。但我下面提到的代码是给出所有行而不是前2个分数。

select abc.score
from #b as a
cross apply (
    select top 2 score
    from #b as 
    where b.name = a.name
    order by b.score desc
) as abc

您能否告诉我上述代码中的错误。

Answer 1

请检查以下查询是否适用于您的情况。

create table #b
(name varchar(30), score int);


insert into #b (name, score)
values ('mohit',12),
('pradeep',30),
('garry',42)


SELECT name,
       score,
       ROW_NUMBER() OVER(ORDER BY Score) RN
INTO #c
FROM #b

SELECT name,
       score,
       CONVERT(NUMERIC,score)/
       (SELECT SUM(score)
        FROM #c
        WHERE RN <= 2) Percentage
FROM #c
WHERE RN <= 2

为什么交叉应用是给出所有行而不是前N

1 个答案: