Question

如果http出站网关抛出httpstatuscodeexception ......它会冒泡到我调用网关方法的地方。我似乎无法抓住那里的例外

我有以下配置

<int:channel id="responseChannel" />

<int:gateway id="someGateway"  service-interface="someinterface"       default-request-channel="requestChannel"      default-reply-channel="responseChannel"        default-reply-timeout="${reply.timeout}"> 
<int:method name ="somemethod">

</int:gateway> 

<int:chain id="some-gateway-chain" input-channel="requestChannel" output-    channel="responseChannel">  
<int:object-to-json-transformer />
<int-http:outbound-gateway       url-expression="some url"         http-method="POST"         expected-response-type-expression="some.RESPONSE_TYPE"     request-factory="somehttpClientFactory" reply-timeout="${reply.timeout}"/>
</int:chain>

编辑：--------------------------------------------- ----------

我可以这样做吗

<int:service-activator input-channel="errorChannel" output-channel="some other channel"> 

<int-groovy:script> how do i check if the payload.message.cause is a httpstatuscodeexception and then throw it from here 
</int-groovy:script> </int:service-activator>

Answer 1

向error-channel添加<int:gateway/>并在那里处理异常。错误通道上的消息为ErrorMessage，其有效负载为MessagingException，其属性为failedMessage和cause。

错误流可以抛出另一个异常或返回其他一些结果。

回应编辑：

嗯...

if (payload.cause instanceof ...) {
    throw payload.cause
}
someOtherResult

http出站网关httpstatuscodeexception

1 个答案: