Question

我在sql中有一个像这样的表：

id               billpay
-------------------------
1024             0
1024             0
1024             1
1025             1
1025             1

我想只检索那些有billpay 1的id

请帮我解决这个问题

Answer 1

它应该是这样的： SELECT id FROM tabel WHERE billpay = 1;

Answer 2

试试这个：

select distinct id from yourtable where billpay = 1

Answer 3

select ID
from MyData
Where billpay = 1

Group By ID

分组依据列出唯一ID

select ID
from MyData A
Where not exists (select 'X' from MyData B where B.billpay <> 1 and  B.ID = A.ID)
Group By ID

这将仅列出billpay仅为1的ID

Answer 4

这将按升序检索那些id，其中billpay = 1表中至少有一条记录。 DISTINCT关键字将确保您不会收到具有相同id的多条记录。

SELECT DISTINCT id
  FROM [TableName]
 WHERE billpay = 1
 ORDER BY id ASC

如果要排除那些也有billpay = 0记录的ID，请使用：

SELECT DISTINCT id
  FROM [TableName]
 WHERE billpay = 1
   AND id NOT IN (SELECT id FROM [TableName] WHERE billpay = 0)
 ORDER BY id ASC

此致

Answer 5

试试这个：

SELECT id
FROM mytable
GROUP BY id
HAVING COUNT(CASE WHEN COALESCE(billpay, 0) <> 1 THEN 1 END) = 0

以上内容仅会选择与id相关联的billpay=1，而只会选择billpay=1。

SQL Fiddle Demo

Answer 6

以下查询从ID组中选择ID，其中billpay = 1的记录数与组中的记录数相同

select id 
from bills 
group by id
having sum(billpay) = count(id)

Answer 7

使用NOT EXISTS查找除billplay 1以外的行，使用DISTINCT仅返回找到的每个ID中的一个。

select distinct id
from tablename t1
where not exists (select 1 from tablename t2
                  where t1.id = t2.id
                    and t2.billpay <> 1)

Answer 8

尝试使用GROUP BY + MIN语句排除现有billpay=0

的ID

SELECT id 
FROM yourtable 
GROUP BY id
HAVING MIN(billpay)=1

找出特定的ID

8 个答案: