Question

我在jsp上创建List时遇到问题。我不确定它是否是一个错误（虽然不太可能）或者我实现它的方式存在一些问题。当我尝试在列表对象中存储值时，我得到了这个异常

type Exception report

messageInternal Server Error

descriptionThe server encountered an internal error that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: PWC6033: Error in Javac compilation for JSP

PWC6199: Generated servlet error:
source value 1.5 is obsolete and will be removed in a future release

PWC6199: Generated servlet error:
target value 1.5 is obsolete and will be removed in a future release

PWC6199: Generated servlet error:
To suppress warnings about obsolete options, use -Xlint:-options.

PWC6197: An error occurred at line: 18 in the jsp file: /OrderCheckOut.jsp
PWC6199: Generated servlet error:
diamond operator is not supported in -source 1.5
  (use -source 7 or higher to enable diamond operator)

note The full stack traces of the exception and its root causes are available in the GlassFish Server Open Source Edition 4.1 logs.

首先我虽然可能是会话对象没有保存值，所以我检索了String中的值并且其工作正常。但是我遇到了list的问题。下面是我的Jsp代码.`＆lt;％尝试{ 购物车displayCart =（购物车）session.getAttribute（“getValue”）;

         String firstname=displayCart.getProdRefCode().toString();
          //This is causing problem I suppose
         ArrayList<String>ProdRefCode=new ArrayList<>();
         ProdRefCode.add(firstname);
        } catch (Exception ex) {
    %><p> There is some problem..check..!
        <%
            }
        %>`

任何人都可以帮我把..

任何帮助将不胜感激..

谢谢

Answer 1

您的堆栈跟踪清楚地说明了为什么会出现此问题。您可能使用Java 5，但Diamond运算符是Java 7功能。所以，有两个解决方案

更新到Java 7

请勿使用以下声明中的钻石操作符。

List<String> ProdRefCode = new ArrayList<String>();

Answer 2

而不是像这样声明ArrayList

ArrayList<String>ProdRefCode=new ArrayList<>();

声明ArrayList Like

List<String> ProdRefCode= new ArrayList();

即不要使用＆lt;＆gt;在右侧

在jsp上创建List时出现异常

2 个答案: