angularjs如何使用多个其他过滤器过滤整数?

时间:2015-04-04 04:49:52

标签: angularjs angularjs-ng-repeat angular-filters

我希望这个问题的标题不会让任何人感到困惑 - 但我需要找出一些看似非常基本的东西,但我似乎并没有"得到它" ......

基本上我有多个过滤器,其中两个过滤数字。但是,如果有一个数字是" 1" (加利福尼亚在jsFiddle的例子中)和另一个是" 13" (亚利桑那州)过滤将包括两者如果我选择" 1"。

这是我的HTML:

<div ng-app='app' ng-controller='myController'>
<h3>Records: {{(projects|filter:filter).length}} of {{projects.length}}</h3>
<p><input type="text" name="generalSearch" placeholder="Search Project Title" ng-model="filter.name"></p>
<p><select ng-model="filter.stateID" 
      ng-options="item.stateID as item.state for item in st_option">        </select>
    <select ng-model="filter.countyID" 
      ng-options="item.countyID as item.county for item in co_option | filter:{ co_state_id : filter.stateID }">
  </select></p>

  <p><a href="" id="clear-filter" ng-click="clearFilter()">Reset Filters</a></p>

  <div ng-repeat="project in projects | filter:filter">
    <div>
  <br>Name: {{ project.name }}
  <br>State: {{project.state}}
  <br>County: {{project.county}}
  <br>
  <span ng-hide="{{project.stateID}} "></span>
  <span ng-hide="{{project.countyID}} "></span>
</div>

JAVASCRIPT CODE:

var app = angular.module('app', []);

app.controller('myController', function($scope) {
  $scope.projects = [{
    name: 'First thing',
    state: 'CA',
    stateID: '1',
    county: 'Orange',
    countyID: '191'
  }, {
    name: 'Another Thing',
    state: 'CA',
    stateID: '1',
    county: 'LosAngeles',
    countyID: '190'
  }, {
    name: 'In California',
    state: 'CA',
    stateID: '1',
    county: 'Orange',
    countyID: '191'
  }, {
    name: 'Hey Arizona!',
    state: 'Arizona',
    stateID: '13',
    county: 'Multiple Counties',
    countyID: '3178'
  },{
    name: 'hello Utah',
    state: 'Utah',
    stateID: '14',
    county: 'Utah County',
    countyID: '200'
  }];

  $scope.st_option = [{
    state: "California",
    stateID: "1"
  }, {
    state: "Arizona",
    stateID: "13"
  },{
   state: "Utah",
    stateID: "14"
  }];

  $scope.co_option = [{
    county: "Orange",
    countyID: "191",
    co_state_id: "1"
  }, {
    county: "Multiple Counties",
    countyID: "3178",
    co_state_id: "13"
  }, {
    county: "Sonoma",
    countyID: "218",
    co_state_id: "1"
  }, {
    county: "Los Angeles",
    countyID: "190",
    co_state_id: "1"
  }, {
    county: "Utah County",
    countyID: "200",
    co_state_id: "14"
  }];

  $scope.filter = {};
 $scope.clearFilter = function() {
    $scope.filter = {};
  };
});

我在这里创建了一个jsFiddle:

https://jsfiddle.net/webmastersean/4m2d5n8u/

我知道我需要添加&#34; true&#34;过滤器,但我不知道在哪里或如何。

1 个答案:

答案 0 :(得分:0)

filter有第三个参数,一个比较器函数。作为语法糖,第三个参数也可以取值true来表示严格的比较。这意味着您需要做的就是将:true添加到县过滤器的末尾:

<select ng-model="filter.countyID" 
      ng-options="item.countyID as item.county for item in co_option | filter:{ co_state_id : filter.stateID }:true">
</select>

Updated fiddle。现在当你选择加州时,你只能在加利福尼亚州获得县。