Question

我尝试使用invoiceErrors更新Map<String,List<Map<String,String>>> invoices，如下所示

InvoiceError // is an entity with below attributes
{ String errorMessage,
  String invoiceNumber    
}
ErrorMessage                                          invoiceNumber   
-------------                                       -------------------     
File Error : The file is in an unsupported format   INV-Error_Test1
Line : 1 Invoice does not foot Reported             INV-Error_Test1
Line : 2 MATH ERROR                                 INV-Error_Test1
Line : 3 MATH ERROR                                 INV-Error_Test2
Line : 3 Invoice does not foot Reported             INV-Error_Test2

我试图在下面的地图上实现如果错误消息没有行号，则需要在顶层附加invLineItems.put('error',['INV-Error_Test1' :文件错误：文件格式不受支持]) 否则，错误消息应附加到匹配的INVOICE和linenumber，如下所示

invLineItems = [INV-Error_Test1:[[LINE:1, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test1, INVOICE_TOTAL:22, error : `Line : 1 Invoice does not foot Reported`], 
                                [LINE:2, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test1, INVOICE_TOTAL:24, error : `Line : 2 MATH ERROR`],
                INV-Error_Test2:[[LINE:3, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test2, INVOICE_TOTAL:26, , error : `Line : 3 MATH ERROR | Line : 3 Invoice does not foot Reported`], 
                                [LINE:4, INVOICE_DATE:20150301, INVOICE_NUMBER:INV-Error_Test2, INVOICE_TOTAL:28,]],
                error : [[INV-Error_Test1:`File Error : The file is in an unsupported format`]]

我写了下面的方法来实现上面的

def regex = "^Line\\s(?:(\\d+)\\s)?\\s*:\\s+(\\d+)?.+";
for (e in invLineItems ){
  def errors =  lipErrors.findAll{it.invoiceNumber==e.key} // finding the error messages with the invoice number
  errors.each{  // fetching the line numbre from error message and finding the matching record the invoice number and line number in invLineItems 
     int lineNumber
     if (it.errorMessage.matches(regex)) {
            Pattern p = Pattern.compile("\\d+");
            Matcher m = p.matcher(it.errorMessage);
            if (m.find()) {
                 lineNumber = Integer.parseInt(m.group());
            }
          println "lineNumber = "+lineNumber
        }

    if(e.value['LINE_ITEM_NUMBER'].find{it==lineNumber.toString()}) {
      def data = lipErrors.findAll{it.invoiceNumber==e.key && it.errorMessage.matches("^Line\\s+"+lineNumber+"?\\:\\s+"+lineNumber+"?.+")}
      e.getValue().each{it.put("error", data.errorMessage.join("|"))}

     }   

  }
}

代码看起来不像Groovy并且主要使用传统的java代码，我想知道是否可以使用Groovy方法简化代码

Answer 1

看起来Groovy对我来说足够了:-)除非你想成为超级常规。

但是你可以这样写：

def regex = /^Line\s(?:(\d+)\s)?\s*:\s+(\d+)?.+/
invLineItems.each {e->
    int lineNumber
    if (it.errorMessage ==~ regex) {
        Matcher m = it.errorMessage =~ /\d+/
        if (m.find()) {
             lineNumber = m.group() as Integer
        }           
       println "lineNumber $lineNumber"    
    }
    if(e.value['LINE_ITEM_NUMBER'].find{it==lineNumber.toString()}) {
       def data = lipErrors.findAll{it.invoiceNumber==e.key && it.errorMessage ==~ Pattern.compile("^Line\\s+"+lineNumber+"?\\:\\s+"+lineNumber+"?.+")}  
       e.value.each{it['error'] = data.errorMessage.join("|")}
    }
}

基本上我在尝试使用一些正则表达式运算符，也只使用每个表单进行迭代，使用as关键字进行类型转换。没什么特别的。是的，我摆脱了所有的分号。

Groovy Map <string，list <map <string，string>＆gt;＆gt;数据操作</string，list <map <string，string>

1 个答案: