Question

我正在尝试将一些数据输入数据库，并在成功调用结束时获取access_token。

当我打电话传递这个参数时：

enter image description here

一切顺利，用户注册并保存到数据库中，access_token返回给用户：

enter image description here

但是，当我在deviceId值中添加符号+，=或\时，我得到异常并且没有任何内容保存在数据库中：

enter image description here

{
    "message": "An error has occurred.",
    "exceptionMessage": "Error getting value from 'ReadTimeout' on 'Microsoft.Owin.Host.SystemWeb.CallStreams.InputStream'.",
    "exceptionType": "Newtonsoft.Json.JsonSerializationException",
    "stackTrace": "   at Newtonsoft.Json.Serialization.DynamicValueProvider.GetValue(Object target)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.CalculatePropertyValues(JsonWriter writer, Object value, JsonContainerContract contract, JsonProperty member, JsonProperty property, JsonContract& memberContract, Object& memberValue)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeObject(JsonWriter writer, Object value, JsonObjectContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeDictionary(JsonWriter writer, IDictionary values, JsonDictionaryContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeObject(JsonWriter writer, Object value, JsonObjectContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeObject(JsonWriter writer, Object value, JsonObjectContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeDictionary(JsonWriter writer, IDictionary values, JsonDictionaryContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeObject(JsonWriter writer, Object value, JsonObjectContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeObject(JsonWriter writer, Object value, JsonObjectContract contract, JsonProperty member, JsonContainerContract collectionContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.SerializeValue(JsonWriter writer, Object value, JsonContract valueContract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerProperty)\r\n   at Newtonsoft.Json.Serialization.JsonSerializerInternalWriter.Serialize(JsonWriter jsonWriter, Object value, Type objectType)\r\n   at Newtonsoft.Json.JsonSerializer.SerializeInternal(JsonWriter jsonWriter, Object value, Type objectType)\r\n   at Newtonsoft.Json.JsonSerializer.Serialize(JsonWriter jsonWriter, Object value)\r\n   at System.Net.Http.Formatting.BaseJsonMediaTypeFormatter.WriteToStream(Type type, Object value, Stream writeStream, Encoding effectiveEncoding)\r\n   at System.Net.Http.Formatting.JsonMediaTypeFormatter.WriteToStream(Type type, Object value, Stream writeStream, Encoding effectiveEncoding)\r\n   at System.Net.Http.Formatting.BaseJsonMediaTypeFormatter.WriteToStream(Type type, Object value, Stream writeStream, HttpContent content)\r\n   at System.Net.Http.Formatting.BaseJsonMediaTypeFormatter.WriteToStreamAsync(Type type, Object value, Stream writeStream, HttpContent content, TransportContext transportContext, CancellationToken cancellationToken)\r\n--- End of stack trace from previous location where exception was thrown ---\r\n   at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n   at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n   at System.Runtime.CompilerServices.TaskAwaiter.GetResult()\r\n   at System.Web.Http.Owin.HttpMessageHandlerAdapter.<BufferResponseContentAsync>d__13.MoveNext()",
    "innerException": {
        "message": "An error has occurred.",
        "exceptionMessage": "Timeouts are not supported on this stream.",
        "exceptionType": "System.InvalidOperationException",
        "stackTrace": "   at System.IO.Stream.get_ReadTimeout()\r\n   at Microsoft.Owin.Host.SystemWeb.CallStreams.DelegatingStream.get_ReadTimeout()\r\n   at GetReadTimeout(Object )\r\n   at Newtonsoft.Json.Serialization.DynamicValueProvider.GetValue(Object target)"
    }
}

这是此次通话的型号定义：

public class Registration
    {
        public string UserName { get; set; }
        public string Password{ get; set; }
        public string DeviceId { get; set; }
        public string DeviceName { get; set; }
    }

字段deviceId以UserName的形式保存到数据库中，根据它的定义，它是NVARCHAR（1024）

enter image description here

NVARCHAR是否可能不允许使用非字母和数字的字符？别人有这样的问题吗？

编辑：这是问题所在的方法：

[Route("registration/request")]
public async Task<HttpResponseMessage> RegistrationRequest(Registration model)
{
    try
    {
        MatrixLogManager.Info("Starting token creating.");

        var request = HttpContext.Current.Request;
        var tokenServiceUrl = request.Url.GetLeftPart(UriPartial.Authority) + request.ApplicationPath + "/Token";

        MatrixLogManager.Info("Checking if model is valid.");
        if (!ModelState.IsValid)
        {
            return Request.CreateResponse(BadRequest(ModelState));
        }
        using (MatrixServiceLayerLogin login = new MatrixServiceLayerLogin())
        {
            if (login.LoginUser(model.UserName, model.Password, true, true))
            {
                var personId = login.GetPersonId();

                MatrixLogManager.Debug("User " + model.UserName + "successfully logged in on MatrixSTS.");
                try
                {
                    using (var authRepo = new AuthRepository())
                    {
                        ApplicationUser appUser = new UserFactory().CreateApplicationUser(model, personId);
                        IdentityResult result = await authRepo.RegisterUser(appUser);
                        EMailService.SendEmail(appUser);
                        IHttpActionResult errorResult = GetErrorResult(result);

                        if (errorResult != null)
                        {
                            return Request.CreateResponse(errorResult);
                        }

                        using (var client = new HttpClient())
                        {
                            var requestParams = new List<KeyValuePair<string, string>>
                                                {
                                                    new KeyValuePair<string, string>("grant_type", "password"),
                                                    new KeyValuePair<string, string>("username", appUser.UserName),
                                                    new KeyValuePair<string, string>("password", "0000")
                                                };

                            var requestParamsFormUrlEncoded = new FormUrlEncodedContent(requestParams);
                            var tokenServiceResponse = await client.PostAsync(tokenServiceUrl, requestParamsFormUrlEncoded);
                            var responseString = await tokenServiceResponse.Content.ReadAsStringAsync();
                            var responseCode = tokenServiceResponse.StatusCode;
                            var responseMsg = new HttpResponseMessage(responseCode)
                            {
                                Content = new StringContent(responseString, Encoding.UTF8, "application/json")
                            };

                            responseMsg.Headers.Add("PSK", appUser.PSK);
                            return responseMsg;
                        }
                    }
                }
                catch (Exception ex)
                {
                    MatrixLogManager.Error("Error: ", ex);
                    throw ex;
                }
            }
            else
            {
                return Request.CreateErrorResponse(HttpStatusCode.Unauthorized, "Invalid username or password.");
            }
        }
    }
    catch (Exception ex)
    {
        MatrixLogManager.Error(string.Format("Error while trying registring user: Exception = {0} InnerException {1}", ex.Message, ex.InnerException.Message));
        throw;
    }
}

Try-Catch没有捕获任何异常，真正的异常发生在这里：

public async Task<IdentityResult> RegisterUser(ApplicationUser userModel)
{
    userModel.TwoFactorEnabled = true;
    userModel.PSK = TimeSensitivePassCode.GeneratePresharedKey();

    var result = await _userManager.CreateAsync(userModel, "0000");

    return result;
}

当结果返回客户端的行时。我猜想在之前保存不顺利。我将在代码的这一部分设置try-catch，我将发布异常。

Answer 1

这通常发生在两次回复响应时。

考虑您的方法返回Task<IHttpActionResult>而不是Task<HttpResponseMessage>，并注意在调用时如何将errorResult包裹两次：

return Request.CreateResponse(errorResult);

这可能会让您相信令牌服务中的错误会导致此问题，而事实上双重包装是：）

考虑以下事项：

[Route("registration/request")]
public async Task<IHttpResult> RegistrationRequest(Registration model)
{
    try
    {
        MatrixLogManager.Info("Starting token creating.");

        var request = HttpContext.Current.Request;
        var tokenServiceUrl = request.Url.GetLeftPart(UriPartial.Authority) + request.ApplicationPath + "/Token";

        MatrixLogManager.Info("Checking if model is valid.");
        if (!ModelState.IsValid)
        {
            return BadRequest(ModelState);
        }
        using (MatrixServiceLayerLogin login = new MatrixServiceLayerLogin())
        {
            if (login.LoginUser(model.UserName, model.Password, true, true))
            {
                var personId = login.GetPersonId();

                MatrixLogManager.Debug("User " + model.UserName + "successfully logged in on MatrixSTS.");
                try
                {
                    using (var authRepo = new AuthRepository())
                    {
                        ApplicationUser appUser = new UserFactory().CreateApplicationUser(model, personId);
                        IdentityResult result = await authRepo.RegisterUser(appUser);
                        EMailService.SendEmail(appUser);
                        IHttpActionResult errorResult = GetErrorResult(result);

                        if (errorResult != null)
                        {
                            // MAJOR CHANGE here
                            return errorResult;
                        }

                        using (var client = new HttpClient())
                        {
                            var requestParams = new List<KeyValuePair<string, string>>
                                                {
                                                    new KeyValuePair<string, string>("grant_type", "password"),
                                                    new KeyValuePair<string, string>("username", appUser.UserName),
                                                    new KeyValuePair<string, string>("password", "0000")
                                                };

                            var requestParamsFormUrlEncoded = new FormUrlEncodedContent(requestParams);
                            var tokenServiceResponse = await client.PostAsync(tokenServiceUrl, requestParamsFormUrlEncoded);
                            var responseString = await tokenServiceResponse.Content.ReadAsStringAsync();
                            var responseCode = tokenServiceResponse.StatusCode;
                            var responseMsg = new HttpResponseMessage(responseCode)
                            {
                                Content = new StringContent(responseString, Encoding.UTF8, "application/json")
                            };

                            responseMsg.Headers.Add("PSK", appUser.PSK);
                            return responseMsg;
                        }
                    }
                }
                catch (Exception ex)
                {
                    MatrixLogManager.Error("Error: ", ex);
                    throw ex;
                }
            }
            else
            {
                return Request.CreateErrorResponse(HttpStatusCode.Unauthorized, "Invalid username or password.");
            }
        }
    }
    catch (Exception ex)
    {
        MatrixLogManager.Error(string.Format("Error while trying registring user: Exception = {0} InnerException {1}", ex.Message, ex.InnerException.Message));
        throw;
    }
}

Answer 2

我看不到你的完整实现，但如果我采取有根据的猜测，你可能会尝试调用你的登录例程，它会返回一个HttpResponseMessage数据类型（来自你的Register例程）。这两种方法都使用Request.CreateResponse来创建响应。

看问题是，您正在尝试序列化已经序列化的HttpResponseMessage。您的Login方法将调用Request.CreateResponse来创建HttpResponseMessage，您可能只是转过来并且＆＃34;传递＆＃34;你的Register方法（但很可能通过另一个Request.CreateResponse方法调用汇集它 - 这是你遇到麻烦的地方）。这是一个隐含的＆＃34;错误和难以捕捉 - 像棋手一样盯着国际象棋棋盘几个小时。

现在解决方案：只需将登录方法的结果作为注册方法的结果传递，而无需＆＃34;处理＆＃34;它通过Request.CreateResponse方法。如果您是Rest返回状态代码的纯粹主义者，则可以在返回Register方法之前更改返回的状态代码（因为Login可能具有OK [200]的状态代码 - 而更好的做法是返回CREATED [ 201]在注册休息终点）。

错误：ASP.NET WebAPI中的System.InvalidOperationException

2 个答案: